During the 2009 holiday season, 436 randomly sampled American adults were surveyed regarding their average spending on Black Friday. A 95% confidence interval based on this sample is ($80.31,$89.11). (a) What is the margin of error of the interval? (b) A local news anchor claimed that the average spending was $100. Has this claim statistical evidence or not? Explain. (c) Determine the sample mean x and the sample standard deviation s of the sample.

During the 2009 holiday season, 436 randomly sampled American adults were surveyed regarding their average spending on Black Friday. A 95% confidence interval based on this sample is ($80.31,$89.11). (a) What is the margin of error of the interval? (b) A local news anchor claimed that the average spending was $100. Has this claim statistical evidence or not? Explain. (c) Determine the sample mean x and the sample standard deviation s of the sample.

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Description: During the 2009 holiday season, 436 randomly sampled American adults were surveyed regarding their average spending on Black Friday. A 95% confidence interval based on this sample is ($80.31,$89.11).(a) What is the margin of error of the interval?(b)

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter8: Sequences, Series, And Probability

Section8.7: Probability

Problem 58E: What is meant by the sample space of an experiment?

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