In C, implement the function that gets an array of ints and its length, and returns the maximum of the absolute values. int max_abs (const int* arr, int len); For example: On input [1, -3, 7, 4] the function should return 7. On input [2, -3, 2, -4] the function should return 4. On input [0, -3, 2] the function should return 3.
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In C, implement the function that gets an array of ints and its length, and returns the maximum of the absolute values.
int max_abs (const int* arr, int len);
For example:
- On input [1, -3, 7, 4] the function should return 7.
- On input [2, -3, 2, -4] the function should return 4.
- On input [0, -3, 2] the function should return 3.
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- Write a function in c programming language that gets an array of points ( function is defined as : typedef struct{ int x; Int y; } point; ) and sorts the array using qsort().Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)1⁄2 is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation:(1,1) is first because 12+12=2 is the smallest(3,2)…Implement a C function, named median, that receives two arrays as parameters passed and returns the median of the values stored in these two arrays. The two arrays are sorted. The prototype of the function MUST be: double median(int a[], int b[], int sizeA, int sizeB);For example, if I have int a[] = {1, 2, 10, 12, 100}; and int b[] = {3, 11, 20, 500, 600}; then the median is (11+12)/2 = 11.5.Write a function in c++ is ordered that takes an integer array and its size as parameters and returns true if the array elements are ordered in nondecreasing order and returns false if not. For example, integers in {10,0,1,1,5,1009} are ordered in nondecreasing order. On the other hand, integers in {1, 2, 3, 8, 4, 19} are not since 8 > 4
- in C PROGRAMMING LANGUAGE AND COMMENT EVERY LINE SO I CAN UNDERSTAND EVERY STEP PLEASE, A C program can represent a real polynomial p(X) of degree n as an array of the real coefficients al, al, ..., an (an ‡ 0). p(X) = a0 + a1X + a2 X2 + . . .+ anXn Write a program that inputs a polynomial of maximum degree 8 and then evaluates the polynomial at various values of x. Include a function get_poly that fills the array of coefficients and sets the degree of the polynomial, and a function eval_poly that evaluates a polynomial at a given value of x. Use these function prototypes: void get_poly ( double coeffIl, int* degreep); double eval_poly( const double coeffIl, int degree, double x);IN C Programing Let us define the weighted sum of an integer array a[0], a[1], a[2], …, a[n-1] be a[0]*1 + a[1]*2 + a[2]*3 + …+a[n-1]*n. For example, the weighted sum of the array [5,2,6] would be 5*1+2*2+6*3 = 27. Write a recursive function that takes in an array numbers and its length n, and returns its weighter sum. You can assume n is non-negative integer. int weightedSum(int numbers[], int n) {Write a C function countEven() that takes an integer array and the number of elements in the array as parameters, finds and returns the number of even numbers in the array. Prototype: int countEven(int ar[], int n);
- write a program in c# to find a sequence of neighbor number in an array , which has a sum of certain number S. Example: {2,3,1,4,2,5,8}, S=11 {4,2,5}Implement in C Programming 6.11.2: Modify an array parameter. Write a function SwapArrayEnds() that swaps the first and last elements of the function's array parameter. Ex: sortArray = {10, 20, 30, 40} becomes {40, 20, 30, 10}. #include <stdio.h> /* Your solution goes here */ int main(void) { const int SORT_ARR_SIZE = 4; int sortArray[SORT_ARR_SIZE]; int i; int userNum; for (i = 0; i < SORT_ARR_SIZE; ++i) { scanf("%d", &sortArray[i]); } SwapArrayEnds(sortArray, SORT_ARR_SIZE); for (i = 0; i < SORT_ARR_SIZE; ++i) { printf("%d ", sortArray[i]); } printf("\n"); return 0;}In C++, write a program that reads in an array of type int. You may assume that there are fewer than 20 entries in the array. The output must be a two-column list. The first column is a list of the distinct array elements and the second column is the count of the number of occurences of each element.
- Write a C program that checks whether the N real numbers entered by the user on the keyboard are in order from small to large. In your program, you need to write a function that checks whether a given double array is in order from small to large, returns 1 for ordered arrays, 0 for unordered arrays. The function must be recursive and no loops should be used within the function.Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…In C Write a function that gets an array of points (see definition in assignment3.) and sorts the array using qsort().Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)1⁄2 is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation:(1,1) is first because 12+12=2 is the smallest(3,2) is next because 32+22 = 13 is the second smallestBoth (3,4)…