E and F are mutually exclusive events. P (E) = 0.91; P(F) =0.42 . Find P (E| F )

Victoria plays college soccer. She makes a goal 70% of the time she shoots. Victoria is going to attempt two goals in a row in the next game. A = the event Victoria is successful on her first attempt. P(A) = 0.7. B = the event Victoria is successful on her second attempt. P(B) = 0.7. Victoria tends to shoot in streaks. The probability that she makes the second goal given that she made the first goal is 0.8.a. What is the probability that she makes both goals?  b. What is the probability that Victoria makes either the first goal or the second goal?

Let f = {(5,3),(8,9),(3,8)} and g = 5x +4. Find f(3) + g(3). %3D

Fifty percent of consumers prefer to purchase electronics online. You randomly select 8 consumers. Find the probability that the number of consumers who prefer to purchase electronics online is more than five Find the probability that the number that prefer to purchase electronics online is more than five. P(x > 5) = (Round to three decimal places as needed.)

Car inspection: Of all the registered automobiles in Colorado, 5% fail the state emissions test. Fifteen automobiles are selected at random to undergo an emissions test. Round the answers to at least four decimal places. 8 Part: 0/4 Part 1 of 4 (a) Find the probability that exactly three of them fail the test. The probability that exactly three of them fail the test is X 5

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P ( -2.53 < z < 0.65)

Find the probability of the indicated event if P(E) = 0.25 and P(F) = 0.35. Find P(E or F) if P(E and F)= 0.20. P(E or F) =| (Simplify your answer.)

From Actuarial Math A telemarketer of an insurance company makes repeated calls to persons on a computer generated list. The probability of making a sale on any individual call is p= 0.1. Successive calls are independent. Let N be the number of unsuccessful calls before the first sale. What is the probability of making exactly 5 unsuccessful calls before (a) the third sale is made? (b) Find E(N) and Var(N) using E(N) = rß and Var(N) = rß(1+ B). %3D

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