e class of models for population growth rates in marine fisheries assumes that the harvest from fishing is proportional to the population size. For one such model, we have the the following formulla, where Gis the growth rate of the population, in millions of tons of fish per year, and n is the population size, in milions of tons of fish. 0.3 (a) Make a graph of G versus n. Include values of n up to i million tons. G 0.10 02 04 10" 0.08 0.02 0.06 0.01 0.04 -0.06 0.02 -0.08 0.2 0.6 08 1.0 -0.1아 0.10 - 0.10- 0.0s 0.00 2 0.8 0.2 04 0.6 10 0.01 -0.05 0.02 o-0.10 0.2 0.4 0.6 10 (b) Use functional notation to epress the growth rate if the population size is 0.28 million tons. d028 x ) Calculate the value. (Round your answer to two decimal places-) 001232 xx million tons per year (c) Calculate G0.62). (Round your ansver to two decimal places.) G(0.62) = 0014 x million tons per year Explain in practical terms what your answer means. If the population size is 0.62 million tons, then the population is increasing at a rate of 0.01 million tons per year. O F the population size is 0.62 million tons. then the population is decreasing at a race of 0.01 million tons per year O F the population size is 0.62 million tons, then the growth rate is increasing at a rate of 0.01 million tons per year. e F the population size is 0.62 million tons, then the growth rate is decreasing at a rate of 0.01 million tons per year. C) At what population size is the grovth rate the largest? (Round your answer to two decimal places.) 025 v million tons

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Chapter2: Graphical And Tabular Analysis
Section2.6: Optimization
Problem 7E: Marine Fishery One class of models for population growth rates in marine fisheries assumes that the...
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Please answer parts (b) and (c).

(b) Use functional notation to express the growth rate if the population size is 0.28 million tons.
G0.28
|× )
Calculate the value. (Round your answer to two decimal places.)
0.01232
x million tons per year
(c) Calculate G(0.62). (Round your answer to two decimal places.)
G(0.62) = -0.014
x million tons per year
Explain in practical terms what your answer means.
If the population size is 0.62 million tons, then the population is increasing at a rate of 0.01 million tons per year.
If the population size is 0.62 million tons, then the population is decreasing at a rate of 0.01 million tons per year.
If the population size is 0.62 million tons, then the growth rate is increasing at a rate of 0.01 million tons per year.
If the population size is 0.62 million tons, then the growth rate is decreasing at a rate of 0.01 million tons per year.
Transcribed Image Text:(b) Use functional notation to express the growth rate if the population size is 0.28 million tons. G0.28 |× ) Calculate the value. (Round your answer to two decimal places.) 0.01232 x million tons per year (c) Calculate G(0.62). (Round your answer to two decimal places.) G(0.62) = -0.014 x million tons per year Explain in practical terms what your answer means. If the population size is 0.62 million tons, then the population is increasing at a rate of 0.01 million tons per year. If the population size is 0.62 million tons, then the population is decreasing at a rate of 0.01 million tons per year. If the population size is 0.62 million tons, then the growth rate is increasing at a rate of 0.01 million tons per year. If the population size is 0.62 million tons, then the growth rate is decreasing at a rate of 0.01 million tons per year.
One class of models for population growth rates in marine fisheries assumes that the harvest from fishing is proportional to the population size. For one such model, we have the the following formula, where Gis the growth rate of the population, in millions of tons of fish per year, and n is the population size, in millions of tons of fish.
G = 0.4n(1 -)- 0.3n
(a) Make a graph of G versus n. Include values ofn up to 1 million tons.
G
G
0.10
n
1.0
0.08
0.2
0.4
0.6
0.8
0.02
0.06
0.04
0.04
-0.06
0.02
-0.08
0.2
0.4
0.6
0.8
1.0
-0.10f
G
0.10
0.1아
0.08
0.05
0.06
n
0.2
0.4
0.6
0.8
1.0
0.04
-0.05
0.02
O-0.10
0.2
0.4
0.6
0.8
1.0
(b) Use functional notation to express the growth rate if the population size is 0.28 million tons.
C 0.28
Calculate the value. (Round your answer to two decimal places.)
0.01232
x million tons per year
(c) Calculate G(0.62). (Round your answer to two decimal places.)
G(0.62) = -0.014
x million tons per year
Explain in practical terms what your answer means.
O f the population size is 0.62 million tons, then the population is increasing at a rate of 0.01 million tons per year.
O f the population size is 0.62 million tons, then the population is decreasing at a rate of 0.01 million tons per year.
O f the population size is 0.62 million tons, then the growth rate is increasing at a rate of 0.01 million tons per year.
O If the population size is 0.62 million tons, then the growth rate is decreasing at a rate of 0.01 million tons per year.
(d) At what population size is the growth rate the largest? (Round your answer to two decimal places.)
0.25
v million tons
Transcribed Image Text:One class of models for population growth rates in marine fisheries assumes that the harvest from fishing is proportional to the population size. For one such model, we have the the following formula, where Gis the growth rate of the population, in millions of tons of fish per year, and n is the population size, in millions of tons of fish. G = 0.4n(1 -)- 0.3n (a) Make a graph of G versus n. Include values ofn up to 1 million tons. G G 0.10 n 1.0 0.08 0.2 0.4 0.6 0.8 0.02 0.06 0.04 0.04 -0.06 0.02 -0.08 0.2 0.4 0.6 0.8 1.0 -0.10f G 0.10 0.1아 0.08 0.05 0.06 n 0.2 0.4 0.6 0.8 1.0 0.04 -0.05 0.02 O-0.10 0.2 0.4 0.6 0.8 1.0 (b) Use functional notation to express the growth rate if the population size is 0.28 million tons. C 0.28 Calculate the value. (Round your answer to two decimal places.) 0.01232 x million tons per year (c) Calculate G(0.62). (Round your answer to two decimal places.) G(0.62) = -0.014 x million tons per year Explain in practical terms what your answer means. O f the population size is 0.62 million tons, then the population is increasing at a rate of 0.01 million tons per year. O f the population size is 0.62 million tons, then the population is decreasing at a rate of 0.01 million tons per year. O f the population size is 0.62 million tons, then the growth rate is increasing at a rate of 0.01 million tons per year. O If the population size is 0.62 million tons, then the growth rate is decreasing at a rate of 0.01 million tons per year. (d) At what population size is the growth rate the largest? (Round your answer to two decimal places.) 0.25 v million tons
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