(e) This microprocessor uses the specifications shown in Figure Q1(e) for 16-bit floating point number representation. If the decimal value is 0.1875, determine the 16-bit floating point representation. The mantissa is normalised. A normalised mantissa has a logic 'I' after its binary point. E.g.. Normalised mantissa: 0.1xxxxxxx Non-normalised mantissa: 0.01xxxxxx Non-normalised mantissa: 0.001xxxxx Bit 15 8 bits Mantissa (M) is an unsigned fixed point fraction Decimal value 8 bits Exponent (E) is in 2's complement representation (0.M) - 2 Figure Ol(e)
(e) This microprocessor uses the specifications shown in Figure Q1(e) for 16-bit floating point number representation. If the decimal value is 0.1875, determine the 16-bit floating point representation. The mantissa is normalised. A normalised mantissa has a logic 'I' after its binary point. E.g.. Normalised mantissa: 0.1xxxxxxx Non-normalised mantissa: 0.01xxxxxx Non-normalised mantissa: 0.001xxxxx Bit 15 8 bits Mantissa (M) is an unsigned fixed point fraction Decimal value 8 bits Exponent (E) is in 2's complement representation (0.M) - 2 Figure Ol(e)
Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
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Transcribed Image Text:(e) This microprocessor uses the specifications shown in Figure Q1(e) for 16-bit floating
point number representation. If the decimal value is 0.1875, determine the 16-bit
floating point representation. The mantissa is normalised.
A normalised mantissa has a logic 'I' after its binary point. E.g.,
Normalised mantissa: 0.1xxxxxxx
Non-normalised mantissa: 0.01xxxxxx
Non-normalised mantissa: 0.001xxxxx
Bit 15
8 bits
Mantissa (M) is an unsigned
fixed point fraction
8 bits
Exponent (E) is in 2's
complement representation
Decimal value = (0.M)* 2
Figure 01(e)
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