e.instructure.com/cours The average height of an NBA player is 6.698 feet. A random sample of 30 players' heights from a major college basketball program found the mean height was 6.75 feet with a standard deviation of 5.5 inches. At a = 0.05, is there sufficient evidence to conclude that the mean height differs from 6.698 feet? STEP 1. State the null and alternate hypothesis A C Ho:u = 6.698 Ho:u = 6.698 |3| Ho:e 6.698 Ho:u = 6.698 %3D %3| H1:H # 6.698 H1:H > 6.698 H1:µ < 6.698 H1:4 = 6.75 The hypotheses are (Enter an UPPER CASE Letter Only.) STEP 2. State the critical value(s). Enter the appropriate letter. B C 1.28 z =-1.65 z= -2.33 z=1.28 z%= H. 1.65 z 2.33 z D !! F1.65 z =F1.96 E.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 26PFA
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The average height of an NBA player is 6.698 feet. A random sample of
30 players' heights from a major college basketball program found the
mean height was 6.75 feet with a standard deviation of 5.5 inches. At a =
0.05, is there sufficient evidence to conclude that the mean height differs
from 6.698 feet?
STEP 1. State the null and alternate hypothesis
A
Ho:4
6.698
Ho:H
6.698
Ho:e
6.698
Ho:u = 6.698
H1:4 # 6.698
H1:µ > 6.698
H1:µ < 6.698
H1:u = 6.75
The hypotheses are
(Enter an UPPER CASE Letter
Only.)
STEP 2. State the critical value(s). Enter the appropriate letter.
A
В
C
z=-1.28 z = -1.65 z= -2.33 z=
H.
1.28 z 1.65 z 2.33 z =71.65|z =
!!
71.96 z
Transcribed Image Text:eycollege.instructure.com/courses The average height of an NBA player is 6.698 feet. A random sample of 30 players' heights from a major college basketball program found the mean height was 6.75 feet with a standard deviation of 5.5 inches. At a = 0.05, is there sufficient evidence to conclude that the mean height differs from 6.698 feet? STEP 1. State the null and alternate hypothesis A Ho:4 6.698 Ho:H 6.698 Ho:e 6.698 Ho:u = 6.698 H1:4 # 6.698 H1:µ > 6.698 H1:µ < 6.698 H1:u = 6.75 The hypotheses are (Enter an UPPER CASE Letter Only.) STEP 2. State the critical value(s). Enter the appropriate letter. A В C z=-1.28 z = -1.65 z= -2.33 z= H. 1.28 z 1.65 z 2.33 z =71.65|z = !! 71.96 z
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