Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the discharge of a 1.33 F capacitor charged to 74.5 kV. Rosa rightly reckons that she can enhance the effect of each laser pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose dielectric constant is 453, with one possessing a dielectric constant of 927. Find the electric potential energy U, of the original capacitor when it is charged. U1 = Calculate the electric potential energy U2 of the upgraded capacitor when it is charged.

University Physics Volume 2
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ISBN:9781938168161
Author:OpenStax
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Chapter8: Capacitance
Section: Chapter Questions
Problem 63P: A parallel-plate capacitor has square plates that are 8.00 cm on each side and 3.80 mm apart. The...
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Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by
the discharge of a 1.33 F capacitor charged to 74.5 kV. Rosa rightly reckons that she can enhance the effect of each laser
pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's
filling, whose dielectric constant is 453, with one possessing a dielectric constant of 927.
Find the electric potential energy Uj of the original capacitor when it is charged.
U1 =
J
Calculate the electric potential energy U2 of the upgraded capacitor when it is charged.
U2 =
J
Transcribed Image Text:Each shot of the laser gun most favored by Rosa the Closer, the intrepid vigilante of the lawless 22nd century, is powered by the discharge of a 1.33 F capacitor charged to 74.5 kV. Rosa rightly reckons that she can enhance the effect of each laser pulse by increasing the electric potential energy of the charged capacitor. She could do this by replacing the capacitor's filling, whose dielectric constant is 453, with one possessing a dielectric constant of 927. Find the electric potential energy Uj of the original capacitor when it is charged. U1 = J Calculate the electric potential energy U2 of the upgraded capacitor when it is charged. U2 = J
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