eas. s F(S) = S3+9

Q: determine the inverse Laplace transform s2 + 12 x(s) : %3| s (s + 2) (s + 3)

A:

Q: Find the Inverse Laplace Transform 1 7 F(s) : s3 (s² + 16) F(s) = s2 + 2s + 5

A:

Q: S F(s) = (s+5)6

A: Use partial fractions to split the function then use laplace table.

Q: find the inverse Laplace transform of the given function. 5.F(s)=2s−3s2−4

A: Given function is: Since the Laplace transform of: And

Q: Determine the inverse Laplace transform. l 1+s s3

A:

Q: Find the inverse Laplace transform of the following: H(s)=2e-s/s2(s+3)

A: Thanks for the question :)And your upvote will be really appreciable ;)

Q: s² (s – 1) 2 S

A:

Q: Evaluate the inverse Laplace transform L^-1 { (1 + e^-2s)^2 / (s + 2) }

A: Solution

Q: Find the inverse Laplace transform of (s – 2)e-s s2 – 4s +3 | F(s) =

A:

Q: Find the inverse Laplace transform F(s) = 2s+1 s²+s+1

A:

Q: Find the inverse Laplace transform of s2 + 12 s² ( s² – 4 ) F(x)

A: To find the Inverse Laplace transform of F(x)=s2+12s2(s2-4)

Q: Find the inverse Laplace transform of s²+6'

A: Formula : L-1 ss2+a2 = cos(at)

Q: determine the inverse Laplace transform of F.

A:

Q: Find the inverse Laplace transform 3s +1 b) s(s? +1)

A: We need to find the inverse Laplace of Fs = 3s + 1ss2 + 1.  First, we need to find the partial…

Q: Find the inverse LaPlace transform F(s) = 5s +3 (s-1) (s²+2s+5)

A:

Q: 1 Find the Inverse Laplace transform of F(s) : (s+1)(s²–1)

A: The given expression is Fs=1s+1s2-1 Write the partial fractions  Fs=1s+1s2-1=1s+1s+1s-1…

Q: 2e-2s 22. F(s) = s2 – 4

A:

Q: S s2 + 2 s3 S

A:

Q: determine the inverse Laplace transform of F.

A:

Q: Find the inverse Laplace transform of: s² + 4 S

A: Inverse Laplace

Q: Find the inverse Laplace transform: 1 (s(s² + 1).

A:

Q: 10 2. F (s) s2 +4s+4

A:

Q: T-1 S '(s-2)4 2)4]

A:

Q: Find the inverse Laplace transform F(s) = s² +9 (S²-9)²

A:

Q: find the inverse Laplace transform of the given function. 2.F(s)=4(s−1)3

A:

Q: s+5 s2+9

A: Given term is: s+5s2+9

Q: Find the inverse Laplace transform of (s²+s+2)(s+4)*

A: We need to find the inverse Laplace transform of ss2+s+2s+4. So,…

Q: Find the inverse laplace transform of : -S -2s 1– 2e + e F(S) = (6? + 4) (s)

A: To Find the inverse Laplace Transform of given Problem first we will use the linearity property then…

Q: Find the Inverse Laplace Transform. Y (s) (10s + 8) తాతి s3

A:

Q: 3) F(s)=- s(s+a

A: To solve this problem, we use the standered result of   inverse laplace transformation.

Q: find the inverse Laplace transform of the given function. 13.F(s)=3!(s−2)4

A:

Q: Evaluate the Inverse Laplace Transform S-1 F(s)= (s1)(s?1)

A: The solution is given as

Q: Find the inverse laplace transform of H(s)= 8/(3(s^2) + 12) + 7/s^5

A:

Q: 1 2) F(s)=- s'+4s

A:

Q: Find the inverse Laplace Transform of: s- 1 (s – 2)(s – 3)(s – 4)

A:

Q: Findthe Laplace transform, L{t2sin(t)}.

A:

Q: 8s – 16 (s² + s)(s² + 1) J

A: Solution:-

Q: Determine the Inverse Laplace Transform of F(s) = 8(s+1) %3| s(s2 +4s +8)

A:

Q: Find the inverse Laplace transform of S (s2+s+2) (s+4)

A: Find

Q: Find the inverse Laplace transform. F(s) = 1/s - 2/s^5/2

A: This question related to inverse laplace transform.

Q: Find the inverse Laplace Transform of  F(s)= 6s/(s2+25) + 3/(s2+25). COMPLETE SOLUTION

A: The solution is given as

Q: 3. Find the inverse Laplace transform of the ff. а. (s+1)(s+2)2 10 b. s(s+2)(s+3)2

A:

Q: Determine the inverse Laplace transform of the following: 5s – 2 F(s) s2(s – 1)(s + 2)

A:

Q: L-1 ( 1 (s+1)(s²-1)

A: A detailed solution is given below.

Q: Find the inverse LaPlace transform F(s) = 5s 2 s² +9

A:

Q: determine the inverse Laplace transform of the given function. 6 s2 + 25

A:

Q: 6s + 15 s >0 s2 + 25

A: The given function is    9s+15s2+25        s>0     we have to find inverse Laplace Transform of…

Q: Find the inverse LaPlace transform F(s) = 3 ²+5 2

A: Given, F(s)= 3/(s²+5) It can also be written as, F(s)= 3/(s²+(√5)²)

Q: Obtain the inverse Laplace transform: 4s+4 s² (s-2)

A:

Q: L{tU(t- 1)}.

A: We have to find Laplace Transform of {tu(t-1)}