I just need clarification what are TL and TH?Where do we get the values from? A completely reversible heat pump produces heat at a rate of 300 kW to warm ahouse maintained at 24°C. The exterior air, which is at 7°C, serves as the source.Calculate the rate of entropy change of the two reservoirs and determine if thisheat pump satisfies the second law according to the increase of entropy principle. COPHP,rev11= 17.47net1-T, /T,1-(280 K)/(297 K)The power required to drive this heat pump, according tothe coefficient of performance, is then7°C300 kW%3Dnet, in= 17.17 kW%3DCOP HP.rev17.47According to the first law, the rate at which heat is removed from the low-temperatureenergy reservoir is300 kW -17.17 kW = 282.8 kW%3Dnet, inThe rate at which the entropy of the high temperature reservoir changes, according to thedefinition of the entropy, is300 kW1.01kW/KTH297 Kand that of the low-temperature reservoir is- 282.8 kW=-1.01kW/KAS,T,280 KThe net rate of entropy change of everything in this system isASAS, + AS, = 1.01 – 1.01 = 0 kW/Ktotalas it must be since the heat pump is completely reversible.

need clarification what is TL and TH

Answered: eat at a rate of 300 I hich is at 7°C,…

Engineering

Mechanical Engineering

eat at a rate of 300 I hich is at 7°C, serves vo reservoirs and det

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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