Educational Television In a random sample of 190 people, 144 said that they watched educational television. Find the 99% confidence interval of the true proportion of people who watched educational television. Round intermediate answers to at least five decimal places. Round your final answers to at least three decimal places.

Q: Use the given data to construct a 98%confidence interval for the population proportion p x = 52 , n…

A: We have given that,  Favorable cases (X) = 52 and sample size (n) = 69 Then,  We will find the 98%…

Q: In a survey of 2262 adults, 719 say they believe in UFOS. Construct a 95% confidence interval for…

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Q: Assume that all necessary conditions were met for creating a confidence interval for a proportion.…

A: Introduction: The 95% confidence interval for the true proportion of all high school students that…

Q: A clinical trial tests a method designed to increase the probability of conceiving a girl. In the…

A: 99% of confidence interval for p p^ = xn = 268335= 45 = 0.8 Significance level α = 1-confidence…

Q: In a survey of 4085 adults, 749 oppose allowing transgender students to use the bathrooms of the…

A: Given,   The sample proportion is,

Q: In a survey of 3905 adults, 719 oppose allowing transgender students to use the bathrooms of the…

A: Find z-critical value:…

Q: In a survey of 4039 ​adults, 719 oppose allowing transgender students to use the bathrooms of the…

A: Consider that p is the true population proportion. Then the point estimate of p is p̂ = x/n, such…

Q: na recent survey of 50 randomly selected college students, 33 said that they believe in the…

A: Given that  Sample size n =50 Favorable cases x =33

Q: Home Internet Access In a recent year, a study found that  78% of adults ages 18 – 29  had internet…

A: From the provided information, population proportion p=0.78. Sample size n=184. Number of successes…

Q: In a survey of 2262 adults, 719 say they believe in UFOS. Construct a 95% confidence interval for…

A: Given problem is :

Q: In a survey of 2310 adults, 706 say they believe in UFOS. Construct a 99% confidence interval for…

A: It is given that sample size (n) is 2,310 and x is 706.

Q: Use the results from the survey about losing sleep. The confidence interval for the proportion is…

A: Based on the given information, the known values are, n=1,035Sample proportionfor losing…

Q: Manual Transmission Automobiles In a recent year, 6% of cars sold had a manual transmission. A…

A: Obtain the 99% confidence interval for the true proportion of college students who drive cars with…

Q: In a survey of 3041 adults, 1426 say they have started paying bills online in the last year.…

A: The number of adults said that they have started paying bills online in the last year (x) is 1426…

Q: Manual Transmission Automobiles In a recent year, 6% of cars sold had a manual transmission. A…

A: The proportion of students who had manual transmissions,  p^=Sample of students who had manual…

Q: A large container contains colored beads. A simple random sample of beads yielded 107 red beads and…

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Q: Educational Television In a random sample of 190 people, 150 said that they watched educational…

A: Solution: Let X be the number of people said that they watched educational television and n be the…

Q: You are interested in finding a 98% confidence interval for the average number of days of class that…

A:

Q: is said that happy and healthy workers are efficient and productive. A company that manufactures…

A:

Q: A drug is used to help prevent blood clots in certain patients. In clinical​ trials, among 4758…

A:

Q: Educational Television In a random sample of 190 people, 145 said that they watched educational…

A: The answer is given below:

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

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Q: 1. Wi-Fi Access A survey of 50 students in grades 4 through 12 found 68% have classroom Wi-Fi…

A: Given that  n=50 , p=68%=0.68

Q: Wi-Fi Access A survey of 57 students in grades 4 through 12 found 69% have classroom Wi-Fi access.…

A:

Q: Home Internet Access In a recent year, a study found that 76% of adults ages18–29 had internet…

A: Given, The sample proportion is, Critical value: Using the z-table, the z-critical value for a…

Q: In a survey of 2270 adults, 715 say they believe in UFOS. Construct a 95% confidence interval for…

A: x = 715 n = 2270

Q: In a survey of 4024 adults, 740 oppose allowing transgender students to use the bathrooms of the…

A:

Q: Construct a confidence interval using the given confidence interval:  given 99%, n=300, = 14.0; the…

A: Given confidence level=99%

Q: 25. A Gallup poll asked each of 2000 randomly selected adults whether they attended a house of…

A: From the provided information, Sample size (n) = 2000 Out of which 750 respondents said yes that is…

Q: In a survey of 3361 adults in a country, 44% believe the economy is getting better. Three weeks…

A: Given Information: In a survey of 3361 adults in a country, 44% believe the economy is getting…

Q: Home Internet Access In a recent year, a study found that 76% of adults ages 18-29 had internet…

A:

Q: Educational Television In a random sample of 195 people, 142 said that they watched educational…

A: From the provided information, Sample size (n) = 195 Out of which 142 said that they watched…

Q: nave taken an online course. s taken, of which 24 have taken an o aple proportion this high or…

A: Given Data population proportion,p = 0.42 NNumber of success = X = 24 sample size n = 64

Q: Determine the margin of error for the confidence interval for the proportion: <0.58<p0.821   The…

A: We have given  confidence interval for the proportion: 0.58&lt;p&lt;0.821 LCL =0.58 UCL=0.821…

Q: It is said that happy and healthy workers are efficient and productive. A company that manufactures…

A: The given information is that the sample of 240 companies showed that 97 of them provide facilities…

Q: 12. How confident? The figure below shows the result of taking 25 SRSS from a Normal population and…

A:

Q: Home Internet Access In a recent year, a study found that 78%  of adults ages 18 – 29 had internet…

A: From the provided information, Sample size (n) = 185 Out of which 159 had access. Sample proportion…

Q: 46. A sample of 5,324 Americans were asked about what matters most to them in a place to live.…

A:

Q: Home Internet Access In a recent year, a study found that 78% of adults ages 18–29 had internet…

A: The answer can be given by finding p and E.

Q: Home Internet Access In a recent year, a study found that 75% of adults ages 18-29 had internet…

A: Given, n= 188 Pr of undergraduate having internet access (p)=167/188=0.88829 q= 1-0.88829=0.11171

Q: In a survey of 4042 adults, 737 oppose allowing transgender students to use the bathrooms of the…

A: x = 737 n = 4042

Q: a. Use the sample data to construct a 95% confidence interval estimate of the percentage of cell…

A:

Q: Educational Television In a random sample of 205 people, 14 said that they watched educational…

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Q: You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You…

A: The formula for the sample size is as follows: Here,zα/2 is the critical value at 90% confidence…

Q: In a survey of 2300 adults, 718 say they believe in UFOS. Construct a 90% confidence interval for…

A: Given: In a survey of 2300 adults , 718 say they believe in UFOs n= 718 and N= 2300  Now we find the…

Q: Home Internet Access In a recent year, a study found that 77% of adults ages 18–29 had internet…

A: Given: n=189, x=165p=xn=165189=0.873 Hence, the estimate of true proportion is 0.873. The critical…

Q: rough (d). mong 4730 patients treated with the drug, 151 developed the adverse reaction of nausea.,…

A: From the provided information, Among 4730 patients treated with the​ drug, 151 developed the adverse…

Q: You randomly select 36 cars of the same model that were sold at a car dealership and determine the…

A: Givensample size(n)=36sample mean(x)=9.75standard deviation(s)=2.39confidence interval=99%

Q: In a survey of 3919 adults, 708 say they have seen a ghost. Construct a 99% confidence interval for…

A:

Q: n a survey of 2111 adults in a recent​ year, 1244 say they have made a New​ Year's…

A: For 90 % CI , α =0.1 Zα2= 1.645 (+NORMSINV(0.05) --Excel function)) ___________________ For 95% CI ,…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.