Educational Television In a random sample of 195 people, 160 said that they watched educational television. Find the 95% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.

Q: Researchers studying the sticky droplets found on spider webs will measure the widths of a random…

A: Solution: As the sample size increases the margin of error also decreases. Then, the width of the…

Q: A survey reveals that 12% of Americans believe Elvis is still alive, with a margin of error of 4…

A: Given: A survey reveals that 12% of Americans believe Elvis is still alive. A margin of error is 4…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Given, n = 1035 For survey about getting a second or part-time job, p = 0.68 For survey about losing…

Q: Assume that all necessary conditions were met for creating a confidence interval for a proportion.…

A: Introduction: The 95% confidence interval for the true proportion of all high school students that…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

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Q: A media research group uses samples of 3500 households to rank TV shows. The group reported that a…

A: It was stated that a media research group uses samples of 3500 households to rank TV shows. The…

Q: Kendall wants to estimate the percentage of vegetarians who are also vegan. She surveys 150…

A:

Q: Determine the point estimate of the population mean and margin of error for the confidence interval.…

A: Given Information: Lower Bound = 18 Upper Bound = 26

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A:

Q: Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born.…

A: It is given that the in the study 300 babies were born and 270 of them were girls i.e.  sample…

Q: Rosetta wants to estimate the percentage of people who rent their home. She surveys 250 individuals…

A: The formula for 100(1-α)% confidence interval for population proportion is,

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

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Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: No of parents surveyed n = 1091 Point estimate p-hat = 0.74 Margin of error E = ± 0.04

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Let x be the number of people who are willing to take a second or part-time job. It is given that…

Q: In a survey of 2708​ adults, 1465 say they have started paying bills online in the last year.…

A: Given information x = 1465 Sample size (n) = 2708

Q: 3.  Find the confidence interval. a) In a Gallup poll of 1000 adults, 649 of them said that they…

A: 3(a) We have given that,  Favorable cases (X) = 649 and sample size  (n) = 1000 Then,  We will find…

Q: A confidence interval was constructed to estimate the proportion of smokers in the U.S.  Use the…

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Q: Interpret the confidence interval. O If Pew Research Center took many samples, 98% of them would…

A: Confidence interval gives the range of values between which the parameter falls with some…

Q: Educational Television In a random sample of 205 people, 143 said that they watched educational…

A:

Q: A sample of 500 applications to a nursing programme included 400 applications from women with the…

A: Given Information: Sample size n=500 If 400 were applications from women, then 500-400=100…

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: researcher wants to estimate the mean commute time of residents in Westchester County. The…

A: Given that  A researcher wants to estimate the mean commute time of residents in Westchester County.…

Q: A market research firm is hired to estimate the percent of adults living in a large city who have…

A: Givenn=450x=387p^=xn=387450=0.86α=1-0.99=0.01α2=0.005zα2=z0.005=2.5758  (from z table)

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

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Q: When 307 college students are randomly selected and surveyed, it is found that 128 own a car. Find a…

A: Given Data Sample Size, n = 307 Number of successes, x = 128 Significance level,…

Q: In a survey of 2301​adults, 746 say they believe in UFOs. Construct a 90% confidence interval for…

A: The given information is that the sample of 2301 adults, 746 say they believe in UFOs.

Q: ed 1294 people whether they performed any volunteer work during the past year. A total of 517 people…

A: The sample proportion is computed as follows,

Q: Educational Television In a random sample of 195 people, 142  said that they watched educational…

A: Given data, n=195 x=142 p=x/n=0.728 z-value at 99% confidence is Zc=2.576

Q: You are planning to buy a cellphone with a good quality in order to attend the online class. The…

A:

Q: Translate the statement into a confidence interval. Approximate the level of confidence.   In a…

A: Solution

Q: . A group of researchers want to find out what is the percentage of men applying to all nursing…

A: It is given that: Sample sizen=300 nmen=45   The sample proportion of men can be calculated as:…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: 96.2% CS = ? (1 - ∞) 100% = 96.2% (1 - ∞) = 0.962 ∞ = 0.038   Z = NOR MSINV (∞/2)     = 2.075…

Q: roportion of US adults who say they never exercise. Round your answers to three decimal places.…

A: Given that  n=1000 , p=20%=0.20

Q: In a survey of 2319 ​adults, 704 say they believe in UFOs.   Construct a 90% confidence interval for…

A:

Q: In a survey of 3372 adults, 1474 say they have started paying bills onine in the last year.…

A:

Q: Educational Television In a random sample of 195 people, 142 said that they watched educational…

A: From the provided information, Sample size (n) = 195 Out of which 142 said that they watched…

Q: In a survey of 3342 adults, 1489 say they have started paying bills online in the last year.…

A: Given Information: To construct a 99% confidence interval for the population proportion and…

Q: In a survey of 2013 adults in a recent​ year, 731 made a New​ Year's resolution to eat healthier.…

A:

Q: A random survey of 430 students was conducted from a population of 2,700 students to estimate the…

A: Given x=215

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: as per our company guidelines we are supposed to answer only first question. Kindly repost other…

Q: Company A invites you to conduct a survey on its consumer satisfaction rate By surveying a few…

A: Given data  p=20%=0.20, ɑ=0.05, MOE=Margin of error=±0.05  n=?

Q: A random survey of 540 students was conducted from a population of 2,300 students to estimate the…

A: Given that  A random survey of 540 students was conducted from a population of 2,300 students to…

Q: You plan to find a confidence interval for the percentage of children who have speech delays. A…

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Q: Translate the statement into a confidence interval. Approximate the level of confidence.   In a…

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Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Given at  99% confidence interval based on this sample is: 1.7 hours to 3.1 hours.  sample mean=?…

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…

A: Since you have asked multiple question, according to our guidelines we will solve the first question…

Q: In a survey of 2130 adults in a recent​ year, 1491 say they have made a New​ Year's resolution.…

A: Solution: Let X be the number of adults say they have made a New year’s resolution and n be the…

Q: Q2- In a survey of 1501 adults, 1051 said that they believe in global warming. a) Find a point…

A: Given Information: Sample size (n) = 1501 adults Out of which x =1051 said that they believe in…

Q: A drug is used to help prevent blood clots in certain patients. In clinical​ trials, among 4899…

A: Obtain the best estimate. The value of best estimate is obtained below: Thus, the value of best…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.