In a survey of 3372 adults, 1474 say they have started paying bills onine in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results

Q: In a survey of 2285 ​adults, 734 say they believe in UFOs.   Construct a 95% confidence interval for…

A: Given that, In a survey of 2285 ​adults, 734 say they believe in UFOs. 95% confidence level

Q: survey of 2542 adults in a recent​ year, 1362 say they have made a New​ Year's resolution.…

A: From the given information we construct 90% and 95% confidence interval.

Q: In a survey of 2755 ​adults, 1417 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 2755 Out if which 1417 say that they have started…

Q: In a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A: Given:  n=4026 x=708

Q: A manager needs to know the proportion of employees who have insurance. He selects 200 employees and…

A:

Q: According to a recent survey of 1600 people, 62 % feel that the president is doing an acceptable…

A: Obtain the 90% confidence interval for the population proportion of people who feel the president is…

Q: You measure 49 textbooks' weights, and find they have a mean weight of 78 ounces. Assume the…

A: You measure 49 textbooks' weights, and find they have a mean weight of 78 ounces. Assume the…

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: In a survey of 2195 adults in a recent​ year, 1454 say they have made a New​ Year's resolution.…

A:

Q: A 95% confidence interval for the proportion p active voters in the municipality of Aibonito is 0.57…

A:

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

A:

Q: In a survey of 3213​ adults, 1433 say they have started paying bills online in the last year.…

A:

Q: In a survey of 3285​ adults, 1424 say they have started paying bills online in the last year.…

A: X = 1424 N = 3285 99% Confidence level

Q: In a survey of 2308 ​adults, 718 say they believe in UFOs.   Construct a 95 % confidence interval…

A: Given information- Sample size, n = 2308 We have given that out of 2345 adults 718 says they believe…

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

A:

Q: A students wants to estimate the proportion of professors who drive pickup trucks. She surveys 250…

A: Given:  Confidence level = 90 % Total number of intervals = 118

Q: When 307 college students are randomly selected and surveyed, it is found that 128 own a car. Find a…

A: Given Data Sample Size, n = 307 Number of successes, x = 128 Significance level,…

Q: In a survey of 2707 ​adults, 1477 say they have started paying bills online in the last year.…

A:

Q: You measure 25 textbooks' weights, and find they have a mean weight of 74 ounces. Assume the…

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Q: In a survey of 3306 ​adults, 1487 say they have started paying bills online in the last year.…

A:

Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

A:

Q: calculate a 99% Confidence Interval for the true probability of success, a 95% Confidence Interval,…

A:

Q: In a survey of 2319 ​adults, 704 say they believe in UFOs.   Construct a 90% confidence interval for…

A:

Q: In a survey of 2270 ​adults, 746 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Given that, Total number of adults = 2270 746 say they believe in UFOs.

Q: ou measure 50 textbooks' weights, and find they have a mean weight of 79 ounces. Assume the…

A: We have given that,  Sample mean (x̄) = 79, population standard deviation (σ) = 12.4 and sample size…

Q: A research institute asked students if they felt vulnerable to identity theft. In the poll, n=1047,…

A:

Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: Use the given confidence interval to find the margin of error and the sample mean.   ​(70.5​,84.7​)

A:

Q: In a survey of 3342 adults, 1489 say they have started paying bills online in the last year.…

A: Given Information: To construct a 99% confidence interval for the population proportion and…

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: In a recent poll, 410 people were asked if they liked dogs, and 93% said they did. Find the Margin…

A: From the provided information, Sample size (n) = 410 93% said they like dogs that is p̂ = 0.93…

Q: n a survey of 2389 adults in a recent​ year, 1399 say they have made a New​ Year's resolution.…

A: The given information are n=2389taken new year resolution (x)=1399p^=xn=13992389=0.5856 The…

Q: In a survey of 3164 ​adults, 1456 say they have started paying bills online in the last year.…

A: The point estimate of the population proportion is the sample proportion. From the given table, 1456…

Q: You measure 38 textbooks' weights, and find they have a mean weight of 51 ounces. Assume the…

A:

Q: A sociologist is interested in surveying workers in computer-related jobs to estimate the proportion…

A: Obtain the estimate value of the proportion of such workers who have changed jobs within the past…

Q: In a recent poll, 310 people were asked if they liked dogs, and 95% said they did. Find the Margin…

A: Find z-critical value:…

Q: Dave is a member of the high school basketball team. Last week, his success rate for shooting a…

A: Solution: From the given information,

Q: a). Find a 93% confidence interval for p, the true crash risk (probability) for novice drivers, also…

A: For novice drivers, sample size n = 371, Number of crashes, X = 24 For expert drivers, sample size n…

Q: Educational Television In a random sample of 205 people, 14 said that they watched educational…

A:

Q: A sample of n = 200 college students are asked if they believe in extraterrestrial life and 120 of…

A: Given information- Confidence level, c = 95% Sample size, n = 200 No. of students who believe in…

Q: In a survey of 2048 adults in a recent​ year, 1217 say they have made a New​ Year's resolution.…

A: According to the provided information, n=2048 x=1217 The sample proportion is given by:…

Q: In a random sample of 200 people, 154 said that they watched educational television. Find the 90%…

A: It is given that in a random sample of 200 people, 154 said that they watched educational…

Q: You measure 35 textbooks' weights, and find they have a mean weight of 51 ounces. Assume the…

A: Mean = 51 Population standard deviation = 11 Sample size, n = 35

Q: A researcher is attempting to calculate a 95% confidence interval for the number of blue Statsian…

A: Note: " Since you have asked multiple question, we will solve the first question for you. If you…

Q: college professor would like to estimate the proportion of students who pull an "all-nighter,"…

A: Given: sample size(n)=100confidence level =99%confidence interval =(0.48,0.62)

Q: In a survey of 2130 adults in a recent​ year, 1491 say they have made a New​ Year's resolution.…

A: Solution: Let X be the number of adults say they have made a New year’s resolution and n be the…

Q: Pew Poll conducted in 2013 surveyed a random sample of 200 adult Americans and 36 of them said that…

A: Given that a random sample of 200 adult Americans and 36 of them said that they had seen a ghost.…

Q: According to a recent survey of 1200 people, 468 feel that the president is doing an acceptable job.…

A:

Q: Refer to the accompanying stayed outside and construct a 90% confidence interval as many of the mean…

A: We have, CI = xbar +/- sigma/sqrt(n)