Educational Television In a random sample of  200  people,  140  said that they watched educational television. Find the  99%  confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.

Q: Educational Television In a random sample of 200 people, 155 said that they watched educational…

A: We have given that,  Sample size (N) = 200 and favorable cases      (X) = 155 Then,  We will find…

Q: A media research group uses samples of 3500 households to rank TV shows. The group reported that a…

A: It was stated that a media research group uses samples of 3500 households to rank TV shows. The…

Q: 25.  At a local college, 200 students were asked if they attended orientation. 112 said that they…

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Q: 1. A survey of 224 children of ages 9 to 17 was conducted shortly after 1986 space-shuttle disaster.…

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Q: Educational Television In a random sample of 205 people, 143 said that they watched educational…

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Q: Trick or Treat In a survey of a random sample of 35 households in the Cherry Creek neighborhood of…

A: It is given that sample size (n) is 200 and number of households turned out the lights and pretended…

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Q: n a survey, the planning value for the population proportion is p*=.25 . How large a sample should…

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Q: Find the margin of error an the 95% confidence interval   -26. A recent survey of 65,000 households…

A: Solution: 26. The confidence level is 0.95. From the given information, p-hat=0.077 and n=65,000.…

Q: A nutritionist wants to know the population of Kindergarten pupils who eat vegetables. A survey…

A: From the provided information, Sample size (n) = 1500 From which 485 pupils ate vegetables, so…

Q: Translate the statement into a confidence interval. Approximate the level of confidence.  In a…

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Q: Left-handed people are rare. Suppose a researcher conducts a survey of 30 people and finds that 4 of…

A: The random variable left-handed people follow normal distribution. We have to construct the 95%…

Q: Educational Television In a random sample of 195 people, 142  said that they watched educational…

A: Given data, n=195 x=142 p=x/n=0.728 z-value at 99% confidence is Zc=2.576

Q: Presidential Travel In a survey of 1004 individuals, 442 felt that President George W. Bush spent…

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Q: n a survey of 3932 ​adults, 718 oppose allowing transgender students to use the bathrooms of the…

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Q: A poll asked for people's opinion on whether closing local newspapers would hurt civic life. 425 of…

A: We have given that, Favorable cases (X) = 425 and sample size (N) = 1002  Then,  We will fins the…

Q: Data collected by child development scientists produced the following 90% confidence interval for…

A: From the given information, let X be the age of the children say their first word. Confidence level…

Q: Education Television In a random sample of 200 people, 154 said that they watched educational…

A: Given that, X = 154 N = 200 90% confidence level

Q: In a survey of 2270 ​adults, 746 say they believe in UFOs.   Construct a 90% confidence interval for…

A: Given that, Total number of adults = 2270 746 say they believe in UFOs.

Q: Educational Television In a random sample of 195 people, 142 said that they watched educational…

A: From the provided information, Sample size (n) = 195 Out of which 142 said that they watched…

Q: Fix the roads! ~ The Township Board of Meridian Township wants to know how much public support there…

A: Given, 90% confidence interval for the actual proportion of Meridian Township residents who are in…

Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: A proportion, p, that many public opinion polls estimate is the number of Americans who would say…

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Q: A marketing firm is interested in studying what types of links are most profitable on their website.…

A: Given Information: Sample size n=50 visitors Out of which x=35 clicked on a particular link. (a) To…

Q: Educational Television In a random sample of 190 people, 144  said that they watched educational…

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Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: It is said that happy and healthy workers are efficient and productive. A company that manufactures…

A: The given information is that the sample of 240 companies showed that 97 of them provide facilities…

Q: Find the 90% confidence interval of the true proportion of people who watched educational…

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Q: A survey of 1000 U.S. adults found that 33% of people said that they would get no work done on Cyber…

A: We need to construct the 95%95\% confidence interval for the population proportion. We have been…

Q: In a random survey of 2221 North Americans 689 of them had blood type A+. Construct a 94% Confidence…

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Q: A media research group uses samples of 6000 households to rank TV shows. The group reported that a…

A: Given that: n=6000 p=19%=0.19 q=1-p=0.81 95% confidence interval

Q: Educational Television In a random sample of 210 people, 148  said that they watched educational…

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Q: a simple random sample of 1200 Americans age 20 and over, 138 of them were found to have Type I…

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Q: In a survey, people were asked whether they thought sun went around the planet Earth or vice versa.…

A: a. It was found that out of the 2152 people, 389 thought the sun went around earth. The sample size…

Q: Question Emilio wants to estimate the percentage of people who have a financial adviser. He surveys…

A: we have to find all values for given questions.....

Q: 46. A sample of 5,324 Americans were asked about what matters most to them in a place to live.…

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Q: Educational Television In a random sample of 210 people, 150 said that they watched educational…

A: Using Excel formula “=NORM.S.INV(1-(0.05/2))”, the critical value for 95% confidence interval is…

Q: Educational Television In a random sample of 195 people, 160 said that they watched educational…

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Q: Use the given confidence interval to find the margin of error and the sample mean.   ​(68.3​,80.9​)…

A: The given confidence interval is (68.3​,80.9​)

Q: The PIIE Bank in ORSP has 650 checking account customers. A recent sample of 50 of these customers…

A: Solution-: Let, X= Number of customers have Visa card with the bank among 50 customers Given: We…

Q: you want to find out the percent of people who use an iPhone so you survey 120 random adults of whom…

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Q: Dave is a member of the high school basketball team. Last week, his success rate for shooting a…

A: Solution: From the given information,

Q: Educational Television In a random sample of 205 people, 14 said that they watched educational…

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Q: In a random sample of 200 people, 154 said that they watched educational television. Find the 90%…

A: It is given that in a random sample of 200 people, 154 said that they watched educational…

Q: One year’s survey results, of 1525 respondents, 846 said that they expected difficulty finding a…

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Q: .A poll questioned 800 students about their views on pizza for lunch at school. The results…

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Q: A recent public opinion poll on gun control found that 54 people interviewed out of the 160…

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Q: Educational Television In a random sample of 200 people, 154 said that they watched educational…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.