# Electric fieldElectron+

Question
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Ch 19, Problem 38

An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 2.0 cm, and the electric field within the capacitor has a magnitude of 2.2 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate?

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Step 1

Given information:

Electric field strength between the plates (E) = 2.2 × 106 V/m

Distance between the two plates (d) = 2 cm = 0.02 m

General information:

Mass of the electron (me) = 9.1 x 10-31 kg.

Charge on the electron (qe) = 1.6022 x 10-19 C.

Step 2

The acceleration (ae) of the ele...

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