electron is near a positve ion of charge +9e and a negative ion of charge -8e (see figure). (Take a = 4.40 um, b=4.20 um, theta = 66 degrees) (a) Find the magnitude and direction of the resultant force on the electron. (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.) (b) Find the magnitude and direction of the electron's instantaneous acceleration (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.)

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An electron is near a positve ion of charge +9e and a negative ion of charge -8e (see figure). (Take a = 4.40 um, b=4.20 um, theta = 66 degrees)

(a) Find the magnitude and direction of the resultant force on the electron. (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.)

(b) Find the magnitude and direction of the electron's instantaneous acceleration (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.)

An electron is near a positive ion of charge +9e and a negative ion of charge -8e (see the figure below). (Take a =
4.40 µm, b = 4.20 µm, and 0 = 66.0°.)
-8e
a
+9e
Electron
3.00 um
Transcribed Image Text:An electron is near a positive ion of charge +9e and a negative ion of charge -8e (see the figure below). (Take a = 4.40 µm, b = 4.20 µm, and 0 = 66.0°.) -8e a +9e Electron 3.00 um
Expert Solution
Step 1

Charge on electron = - 1.6 × 10-19 C

Q= - 8 e = - 8 × 1.6 × 10-19

= 12.8 × 10-19 C

Q= + 9e =+  9 × 1.6 × 10-19 C

      = 14.4 × 10-19 

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