elemental phosphörus in a two step process. In the first step, phosphorus and oxygen react to form diphosphorus pentoxide: P4(s) + 50,(g) 2P,0,(g) In the second step, diphosphorus pentoxide and water react to form phosphoric acid (H,PO): P,05(g) + 3 H,O(1) → 2H;PO,(l) Suppose the yield of the first step is 86.% and the yield of the second step is 97.%. Calculate the mass of phosphorus required to make 6.0 kg of phosphoric acid.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section3.6: The Mole And Chemical Reactions
Problem 3.17E
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Phosphoric acid, a mild acid used among other things as a rust inhibitor, food additive, and etching agent for cavity repair by dentists, can be made from
elemental phosphorus in a two step process. In the first step, phosphorus and oxygen react to form diphosphorus pentoxide:
P4(s) + 502(g) -
2P,05(g)
In the second step, diphosphorus pentoxide and water react to form phosphoric acid (H,PO4):
P205(g) + 3 H,0(1) → 2H;PO,()
Suppose the yield of the first step is 86.% and the yield of the second step is 97.%. Calculate the mass of phosphorus required to make 6.0 kg of phosphoric
acid.
Be sure your answer has a unit symbol, if needed, and is rounded to 2 significant digits.
Transcribed Image Text:Phosphoric acid, a mild acid used among other things as a rust inhibitor, food additive, and etching agent for cavity repair by dentists, can be made from elemental phosphorus in a two step process. In the first step, phosphorus and oxygen react to form diphosphorus pentoxide: P4(s) + 502(g) - 2P,05(g) In the second step, diphosphorus pentoxide and water react to form phosphoric acid (H,PO4): P205(g) + 3 H,0(1) → 2H;PO,() Suppose the yield of the first step is 86.% and the yield of the second step is 97.%. Calculate the mass of phosphorus required to make 6.0 kg of phosphoric acid. Be sure your answer has a unit symbol, if needed, and is rounded to 2 significant digits.
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