ell. Begin with 2.45 mol Cu and multiply by Avoga- 6.022 X 1U SI P Nn = 1.48 X 10 Cu atoms mass tha 24 2.45 mol Cu X dro's number to get to the number of Cu atoms. 1 mol Cu The CHECK Since atoms are small, it makes sense that the answer is large. The given number of moles of copper is almost 2.5, so the number of atoms is almost 2.5 times Avogadro's number. of that FOR PRACTICE 2.6 A pure silver ring contains 2.80 x 1022 silver atoms. How many moles of silver atoms does it contain? Exam 22 allezo9

Question
ell. Begin with 2.45 mol Cu and multiply by Avoga-
6.022 X 1U
SI P Nn
= 1.48 X 10 Cu atoms
mass tha
24
2.45 mol Cu X
dro's number to get to the number of Cu atoms.
1 mol Cu
The
CHECK Since atoms are small, it makes sense that the answer is large. The given number of moles of copper is almost 2.5,
so the number of atoms is almost 2.5 times Avogadro's number.
of that
FOR PRACTICE 2.6 A pure silver ring contains 2.80 x 1022 silver atoms. How many moles of silver atoms does it
contain?
Exam
22
allezo9

Image Transcription

ell. Begin with 2.45 mol Cu and multiply by Avoga- 6.022 X 1U SI P Nn = 1.48 X 10 Cu atoms mass tha 24 2.45 mol Cu X dro's number to get to the number of Cu atoms. 1 mol Cu The CHECK Since atoms are small, it makes sense that the answer is large. The given number of moles of copper is almost 2.5, so the number of atoms is almost 2.5 times Avogadro's number. of that FOR PRACTICE 2.6 A pure silver ring contains 2.80 x 1022 silver atoms. How many moles of silver atoms does it contain? Exam 22 allezo9

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