E(n) = n² h² 8m₂ L2 3² × (6.62607004 × 10-34 Js)² = 8 ×9.1093856 × 10-3¹ kg × (8.4 × 10-¹0)² m² It's a good idea to rearrange this to collect powers of ten; 32 x (6.62607004 × 10-34 J s)² 8 x 9.1093856 × 10-³¹ kg × (8.4× 10¹0)² m² (10-34)2 32 x 6.62607004² 8 x 9.1093856 × 8.4² 10-31 x (10¹0)2 X = 7.68 × 10-¹⁹ J J

E(n) = n² h² 8m₂ L2 3² × (6.62607004 × 10-34 Js)² = 8 ×9.1093856 × 10-3¹ kg × (8.4 × 10-¹0)² m² It's a good idea to rearrange this to collect powers of ten; 32 x (6.62607004 × 10-34 J s)² 8 x 9.1093856 × 10-³¹ kg × (8.4× 10¹0)² m² (10-34)2 32 x 6.62607004² 8 x 9.1093856 × 8.4² 10-31 x (10¹0)2 X = 7.68 × 10-¹⁹ J J

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter29: Nuclear Physics

Section: Chapter Questions

Problem 2P

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Similar questions

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(a) An aspiring physicist wants to build a scale model of a hydrogen atom for her science fair project. If the atom is 1.00 m in diameter, how big should she try to make the nucleus? (b) How easy will this be to do?
Consider Use them k=9.00×10^9 N.m^2/C^2 ε0= 8.85×10^-12 C^2/N.m^2 µ0=4π×10^-7 T.m/A mp=1.67×10^-27 kg me=9.11×10^-31 kg e=1.6×10^-19 C g=10.0 m/s^2 Do not approximate at all ???
Consider Use them k=9.00×10^9 N.m^2/C^2 ε0= 8.85×10^-12 C^2/N.m^2 µ0=4π×10^-7 T.m/A mp=1.67×10^-27 kg me=9.11×10^-31 kg e=1.6×10^-19 C g=10.0 m/s^2
In two equations 5x-3y=3x-10 ; 3x-2y=3y-19. y=? a. 8 b. 6 c. 9 d. 7 e. 10
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The element 218Po (Polonium-218, Z = 84, atomic mass 218.008966 u) can decay through the emission of a β-particle to 218At (Astatine-218, Z = 85, atomic mass 218.00880 u). If all of the energy released is carried away by the β-particle's kinetic energy, calculate the kinetic energy of the β-particle.answer in units of MeV, correct to two decimal places.
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