Equation of Motion(NORMAL AND TANGENTIAL) Fn= Man Ft= Mat Given a 1400 kg car that travels along a road with increasing vertical profile y = 0.0003x². If the constant velocity of the car is 30 m/s. of the distance is at 210m, a. Determine the x-component of the velocity (m/s) of the car. b. Compute the total force (KN). a. Determine the x-component of the velocity (m/s) of the car. b. Compute the total force (KN). Hint: The slope of a line is equivalent to tanø where Ø is an angle measured from the x-a

Equation of Motion(NORMAL AND TANGENTIAL) Fn= Man Ft= Mat Given a 1400 kg car that travels along a road with increasing vertical profile y = 0.0003x². If the constant velocity of the car is 30 m/s. of the distance is at 210m, a. Determine the x-component of the velocity (m/s) of the car. b. Compute the total force (KN). a. Determine the x-component of the velocity (m/s) of the car. b. Compute the total force (KN). Hint: The slope of a line is equivalent to tanø where Ø is an angle measured from the x-a

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.19P: Plot the earths gravitational acceleration g(m/s2) against the height h (km) above the surface of...

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TOPIC: Equation of Motion (NORMAL AND TANGENTIAL) Fn= Man Ft= Mat Given a 1400 kg car that travels along a road with increasing vertical profile y = 0.0003x². If the constant velocity of the car is 30 m/s. of the distance is at 210m, Determine the x-component of the velocity (m/s) of the car. Compute the total force (KN). PLEASE ANSWER WITH A COMPLETE AND DETAILED SOLUTIONS. THANK YOU
Particles C and D are moving in the positive x-direction, with A behind B initially. Particle A has speed 20 m/S and mass 1 g whilst B has speed 12 m/s and mass 3 g. At some time later the particles coalesce. If momentum is conserved, what is the loss in KE? (A) There is a gain in KE of 24 ] (B) 24] (C) 01 since energy is conserved (D) 0.024]
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