S4 - 14, 15 and 16 For the figure shown, use P = 100 kN, L = 300mm,Si = 100 mm and S2 = 180 mm. Assume theSituation 4:diameter of a bolt is 25 mm.PS,2.S,S,14.Solve the shear stress due to force alone.а.118.24 MPaс.98.82 MPab.33.95 MPad.92.80 MPa15.Calculate the maximum shear stress due to moment alone.а.118.24 MPaс.98.82 MPab.33.95 MPad.92.80 MPa16.Determine the maximum shear stress.a.118.24 MPaс.98.82 MPab.33.95 MPad.92.80 MPa

Name: S4 - 14, 15 and 16 For the figure shown, use P = 100 kN, L = 300mm,Si
Uploaded: 2024-03-20T06:56:55.000Z
Channel: Bartleby
Description: S4 - 14, 15 and 16 For the figure shown, use P = 100 kN, L = 300mm,Si = 100 mm and S2 = 180 mm. Assume theSituation 4:diameter of a bolt is 25 mm.PS,2.S,S,14.Solve the shear stress due to force alone.а.118.24 MPaс.98.82 MPab.33.95 MPad.92.80 MPa15.Ca

Answered: For the figure shown, use P = 100 kN, L…

Engineering

Mechanical Engineering

For the figure shown, use P = 100 kN, L = 300mm, 5 = 100 mm and S2 = 180 mm. Assume the diameter of a bolt is 25 mm. 3, P.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.9.4P: Two steel tubes are joined at B by four pins (dp= 11 mm), as shown in the cross section a—a in the...

See similar textbooks

Similar questions

A flange-and-bolt coupling between two shafts carries 12 bolts at a pitch diameter of 18 in. The shafts carry a torque of 50,000 ft-lb. Assuming that this torque is transmitted by shear across the 12 bolts and that these bolts are to be designed for a shear stress s3 = 3,000 lb/sq in., what is the bolt diameter?
A certain circular shaft is subjected to a maximum equivalent bending moment of 36,000 in-lb and a maximum equivalent torque of 42,000 in-lb.The allowable unit stresses are 12,000 psi for bending and 8000 psi for shear. Expressed as a multiple of 1/4 in, the required diameter of the shaft is A.3 1/2 in B. 3 1/4 in C. 3 in D. 3 3/4 in
The compound shaft is attached to a rigid wall at each end. For the bronze segment AB, the diameter is 66 mm and G = 33.38 GPa. For the steel segment BC, the diameter is 40 mm and G = 83.55 GPa. Given that a = 2.12 m and b = 1.44 m, compute the largest torque T (in Nm) that can be applied as shown in the figure if the maximum shear stress is limited to 66.04 MPa in the bronze and 81.48 MPa in the steel. Round off the final answer to two decimal places.
A full circular cross-section shaft will be designed to provide power transmission at 220 (revolution/minute) revolution of a 12300 kW engine. Since the shaft length is 3 m, the material shear modulus is 80 GPa, and the shear yield stress is 190 MPaa) How many kN.m torque should the shaft carry?b) Write down the minimum safe shaft radius in metersc) How many rad is the shaft at the specified minimum radius. found?
A drill drills a hole in a leg of a furniture. Uses a hand-operated drill with a bit of diameter equal to 5.79mm. If the resisting torque supplied by the table is equal to 0.36 N.m, what is the maximum shear stress of the drill bit? If the allowable shear stress in the drill bit is 44.215MPa, what is the maximum resisting toque before the drill binds up?
A circular steel tube of length L = 1.0 m is loaded by torques T a) If the inner radius of the tube is r1 = 45 mm and the measured angle of twist betweenthe ends is 0.5°, what is the shear strain γ1 (in radians) at the inners surface? b) If the maximum allowable shear strain is 0.0004 rad and the angle of twist is to bekept at 0.45° by adjusting the torque T, what is the maximum permissible outer radius(r2)max?
*1Q4 A hollow steel shaft of 100 mm external diameter (D) and 50 mm internal diameter (d) is subjected to a bending moment (M) of 3.6 kN.m. What is the torque may safely be applied if the greater principal stress (67) is 98 MN/m?? 19.48kN.m () 11.63kN.m () 15.22kN.m O 21.27kN.m O
The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If allowable shearing stress in 20mm rivets is 186 MPa, find the maximum allowable force P that can be applied a. 233.734 kN b. 251.813 kN c. 283.406 kN d. 245.916 kN 2. If allowable bearing stress in holes is 1.2Fu where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 563.3 kN b. 460.8 kN c. 683. 6 kN d. 405.9 kN 3. If allowable yielding of gross area is Fy/1.67, where Fy is the yield strength of the plate and which is equal to 250 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534 kN b. 560 kN c. 446 kN d. 503 kN 4. If diameter of hole equals diameter of rivet, what is the net area of edge-3-4-edge in square…
A shaft is 21/2 in. square, and the allowable shearing unit stress for the material is 6000 psi. The torque on the shaft is A. 27,600 in B 20,800 in C. 31,200 in D. 24,100 in
A gantry crane of weight W=100 Kg moves across a bridge with the length I=5 m. The front axle of the crane (which is nearer end A) carries 3/4W whereas the rear axle (nearer end B) carries 1/4 W. The distance of the axles is b = 1/20. Determine the maximum value of the bending moment and enter your answer in N-m units.. Remember to also show all your work (FBDs, calculation steps, etc on the handworked file) HINT: Determine the shear and bending moment equations along the beam. Assume only concentrated loads at the front and rear axles.
PRIOR ANSWERS: Reaction Forces: By = 76.809 Cy = 15.94 Shear Forces: V (× = 10.5- ft (i.e., just to the left of support B)) = -36.75 kips V ( x = 10.5+ ft (i.e., just to the right of support B)) = 40.059 kips V (x = 25.5 ft) = -12.441 kips V (x = 26.5- ft (i.e.. just to the left of support C))= = -15.941 kips Bending moment: M (x = 10.5 ft (i.e., at support B)) = -192.9375 kips-ft M (x = 25.5 ft) = 14.1975 kips-ft
A shaft supported on bearings, 200 mm apart transmits 187 kW and 200 rpm.The maximum bending moment s 2712 N-m. the allowable shearing stress is 53.3 MPa, and the allowable bending stress is 46.7 Mpa. Find the shaft diameter