ermine the length L of the vertical curve mel the length of the vertical curve L on the sketch drawing a line or a curve – as appro resents L PVI BVC EVC
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- A +2.5% grade meets a -1.75% grade at the station 44+25 and elevation 386.96 ft, the length of curve is 800 feet (8 stations). (1) Provide the stakeout for full stations using parabolic method STATION X g1 X (g2-g1) X2 2L Y (Elevation) PVT = PVC = (2) Determine the station and elevation at the high point of the curveA 546m equal tangent crest vertical curve has PVC at Sta 19+274 and at elevation 136m. The initial grade is 6.14% and the final grade is -5.58%. Determine the station of PVT. Note: Do not include the + sign Sample Answer: 15980a simpl3 curve has A radius of 1 0 0 meters and an angle of intersection of the tangents equal to 35°. It is required to change the curve such that the point of tangency should be moved out a distance of 10 meters without changing the direction of the tangents and the stationing of the point of curvature. Find the length of the new tangent. kindly input an illustration and complete sol'n that I can understand.
- A 400m vertical curve joins a +2.70% grade with a -1.50% grade. The PVI is at station 1+500 and elevation 25.00m. The station and elevation at PVC are ?A2) answer the following situations provided; a) a downgrade of 3.2% meets a rising grade of 4.6% at station 73+180, where the elevation is 998m. A sag curve, 440m long, connects the gradelines from A at the downgrade B at the upgrade. Find the elevation of B in meters. b) A 3-degree curve has an angle of intersection of 24 degrees. What is the length of the chord in meters? use chord basis.Note: kindly Give me all right solutions with clear calculations. a.) Compute the offset distance at the SC if the external distance is 13.20mb.) compute the length of the spiral curvec.) compute the maximum design speed od the curve
- PI sta = 18+00, PI elev = 300.00, L = 20 stations, incoming grade = +2%, outgoing grade = -3% The high point of the curve is at station ? Note: I need right solution.. Don't copy from other expert solution.A compound curve has the following properties: 1,= 25-degree, D,= 6.2-degree, 2= 36-degree, D2= |4.5-degree. Compute the stationing of PCC if PC is at station 10+430.Design the curve, of An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. GIVEN DIMENSIONS ON THE ATTACHED PICTURE
- The perpendicular distance between two parallel tangents of a reverse curve is 35m. The azimuth of the back tangent of the curve is 270°00’ and the azimuth of the common tangent is 300°00’. If the radius of the back curve is 150.00 meters and the stationing of P.R.C. is 10 + 140, find the station of the P.T. Use arc definition. Provide a complete solution with the necessary illustrations.SUBJECT: SURVEYING 2 A-3% grade meets a +5% grade at a vertex (El. 146.24m) directly under an overpass bridge having underside elevation of 155.74m. A 5 meters clearance under the bridge and the center of the curve was observed. Determine the elevation of the invert on center when its location from PC is 75m. The pipe has an outside diameter of 0.4 meters and a thickness of 50mm. The backfill is 0.30 meters in depth. The bridge is having a width of 12 meters.An engineer has been decided to connect a tunnel with floor elevation (100.00m) and station (0.00) with bridge elevation (112.50 m) and station (0+450). He suggested vertical curves with equal tangents. Sketch the Figure. Is the crest vertical curve safe to provide sight distance for design speed (70 km/hr.)? Use t=2.5 sec.