Estimate the magnification and focal length of the pitcher of water shown in the figure below. (Assume that the tree is about 57 ft tall and its inverted image is about 1 foot tall. Also assume that the tree is about 210 ft from the pitcher. Include the sign of the value in your answers.) magnification focal length X The response you submitted has the wrong sign. ✓ ft 3.57 Elizabeth Owens/American Association of Physics Teachers

Estimate the magnification and focal length of the pitcher of water shown in the figure below. (Assume that the tree is about 57 ft tall and its inverted image is about 1 foot tall. Also assume that the tree is about 210 ft from the pitcher. Include the sign of the value in your answers.) magnification focal length X The response you submitted has the wrong sign. ✓ ft 3.57 Elizabeth Owens/American Association of Physics Teachers

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter18: Refraction And Lenses

Section: Chapter Questions

Problem 4STP

See similar textbooks

Similar questions

An object is located in water 15 cm from the vertex of a concave surface made of glass with a radius of curvature 10 cm. Where does the image by refraction form and what is its magnification? Use nwater=4/3and nglass=1.5.
An object is located in air 30 cm from the vertex of a concave surface made of glass with a radius of curvature 10 cm. Where does the image by refraction form and what is its magnification? Use nair=1and nglass=1.5. .
If an object is 8 cm away from a converging lens of focal length 2 cm where will the image be? Find the magnification (Draw a ray diagram of how this image is formed to see if your answer is plausible.)
What would be the magnification on an object if the height of the image is 10 cm and the height of the object is 50 cm? Describe the condition of the image, i.e. upright or inverted, enlarged or diminished. Show all work for full credit.
Please its urgent…. I'll give you thumbs up. Use 3 principal rays and the lens/mirror equation to find and describe the image for each of the following. Describe means: real/virtual; erect/inverted; bigger/smaller, magnification; where? position from lens/mirror. An object is placed 30 cm in front of a f = +15 cm lens. A mirror f = -20 cm is placed 20 cm from the lens.
An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 22 cm and one convex surface of radius 19.3 cm. Determine the final image distance from the center of lens. Follow the sign conventions. Express your answer to two significant figures and include the appropriate units. di=? What is the magnification? Follow the sign conventions. Express your answer using two significant figures. m=?
If an 8 cm doll is standing away from a diverging lens and the focal length is 6 m, find the image distance, magnification, and image height from 4, 8, and 10 m away. Determine if the image is real or virtual, inverted or erect, smaller or larger. Use the formula below:
An object is placed 3.4 m in front of a -1.8-m-focal-length (diverging) lens. Where is the image formed, and is it real or virtual? Inverted or upright? Big or small? Sketch the situation, defining all your variables. Include an accurate ray diagram. Please include the ray diagram.
in step 1 why is the image distance -4 cm?
Please find the image distance, image height and magnification. Provide units as well. Thank you
An object is placed 7.0 cm away from a diverging lens whose focal point is at 6.5 cm. Sketch the ray tracing in the space provided; then answer the three questions below about the image that is formed. is the image... 1. real or virtual? 2. upright or inverted? 3. magnified or reduced?
An image seen through a convex mirror cut from a sphere of radius 20cm is exactly half size of the object. Where must the object and image be located? Support your work with a ray diagram. Hint: Remember that virtual distances are negative when using the mirror equation. Follow grading rubric. Explain answer.