Evaluate the commutator [y², 82/8x² +82/8y2] by applying the operators to an arbitrary function f(x, y). Match the items in the left column to the appropriate blanks in the equations on the right. Make certain each equation is complete before submitting your answer. & [y²f(x, y) + y² ºf(2,y)] 4y² [2yf(x, y) + y²! 2y y² 2 0f(s) by 2y² [y² f(x, y) + y ² 0²³f(x,y)] 4y [y², 0²/0x² + 0²/0y2²]f(x, y) = y²(0²/0x² + 0²/Əy²) f(x, y) - (0²/0x² + 0²/0y²)y² f(x, y) 0² f(x, y) ( a² f(x, y) + a² f(x, y)) მ2 əx² 8² f(x, y) მ2 2 0² f(x, y) ?х2 +y² af(x, y) dy y² y ?х2 8² f(x, y) ?х2 8² f(x, y) dy² f(x, y) - Therefore, [y2, 02/0x² + 0²/0y²] = - af(x, y) dy f(x, y) - Reset Help Ə dy af(x, y) dy

Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter10: Introduction To Quantum Mechanics
Section: Chapter Questions
Problem 10.11E: Indicate which of these expressions yield an eigenvalue equation, and if so indicate the eigenvalue....
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Evaluate the commutator [y², 0²/0x² + 0²/0y²] by applying the operators to an arbitrary function f(x, y).
Match the items in the left column to the appropriate blanks in the equations on the right. Make certain each equation is complete before submitting your answer.
Ə
dy
dy
2
y² f(x, y) + y²
4y²
2yf(x, y) + y²
,2
2y
y²
2
af(x,y)
dy
Of(x,y)
dy
2y²
[y²f(x, y) + y² 8² f(x,y)
მყ2
4y
[y², 0² / əx² + 0²/Əy²]ƒ(x, y) = y² (8² / əx² + ə² /Əy²) ƒ(x, y) — (Ə² /Əx² + 0² /Əy²)y²ƒ(x, y)
-
= y²/
=
= y²
a² f(x, y) a² f(x, y).
‚ə² ƒ(x, y)
3² f(x, y))
+
2
дуг
+
a² f(x, y)
dy²
Əx²
0² f(x, y)
მ2
2
+y².
əx²
‚a² f(x, y)
əx²
-y².
2
f(x, y) ₂a² f(x, y)
- y².
2
მყ
მყ2
f(x, y)
Therefore, [y², 0²/0x² + 0²/Əy²]
Of(x, y)
ду
f(x, y) —
Reset Help
ду
af(x, y)
ду
Transcribed Image Text:Evaluate the commutator [y², 0²/0x² + 0²/0y²] by applying the operators to an arbitrary function f(x, y). Match the items in the left column to the appropriate blanks in the equations on the right. Make certain each equation is complete before submitting your answer. Ə dy dy 2 y² f(x, y) + y² 4y² 2yf(x, y) + y² ,2 2y y² 2 af(x,y) dy Of(x,y) dy 2y² [y²f(x, y) + y² 8² f(x,y) მყ2 4y [y², 0² / əx² + 0²/Əy²]ƒ(x, y) = y² (8² / əx² + ə² /Əy²) ƒ(x, y) — (Ə² /Əx² + 0² /Əy²)y²ƒ(x, y) - = y²/ = = y² a² f(x, y) a² f(x, y). ‚ə² ƒ(x, y) 3² f(x, y)) + 2 дуг + a² f(x, y) dy² Əx² 0² f(x, y) მ2 2 +y². əx² ‚a² f(x, y) əx² -y². 2 f(x, y) ₂a² f(x, y) - y². 2 მყ მყ2 f(x, y) Therefore, [y², 0²/0x² + 0²/Əy²] Of(x, y) ду f(x, y) — Reset Help ду af(x, y) ду
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