Evaluate the integral: I = S, dz where C is the circle |z|=1. O (A) I = –27ni. O (B) I = -3Ti. O (C) I = –5mi. O (D) I =-7ni. 2+1 2(2z+1) %3D %3D -

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Chapter2: Second-order Linear Odes
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Complex Analysis :
Evaluate the integral: I J. dz where C is the circle |z|=1.
O (A) I = -27Ti.
O (B) I = -3Ti.
O (C) I = -57i.
O (D) I = -7ri.
2+1
C (2z+1)
%3D
Transcribed Image Text:Evaluate the integral: I J. dz where C is the circle |z|=1. O (A) I = -27Ti. O (B) I = -3Ti. O (C) I = -57i. O (D) I = -7ri. 2+1 C (2z+1) %3D
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