Example 3: Initially block A has a speed of 3 m/s as shown. D block B at t = 6 s. The coefficient of kinetic friction between b Hk = 0.15. The pulleys are weightless and frictionless. %3D V41=3 m/s 10 kg A

Elements Of Electromagnetics
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Can you explain how the Vb 1/2 comes from? Please write the detail, please 

Example 3: Initially block A has a speed of 3 m/s as shown. Determine the speed of
block B at t = 6 s. The coefficient of kinetic friction between block A and the surface is
H = 0.15. The pulleys are weightless and frictionless.
V4,1 = 3 m/s
10 kg
A
30°
B
20 kg
Transcribed Image Text:Example 3: Initially block A has a speed of 3 m/s as shown. Determine the speed of block B at t = 6 s. The coefficient of kinetic friction between block A and the surface is H = 0.15. The pulleys are weightless and frictionless. V4,1 = 3 m/s 10 kg A 30° B 20 kg
Example 3: Initially block A has a speed of 3 m/s as shown. Determine the speed of
block B at t = 6 s. The coefficient of kinetic friction between block A and the surface is
Hk = 0.15. The pulleys are weightless and frictionless.
27
M3VB.y'1 +E]° F,dt =
„dt = M²VB.y'.2
1
VB.y"
A,x
+(2T – 20-9.81). 6 = 20 - v3,y' 2
2
1
= 20.
20-
•V
A,x,2
W
Transcribed Image Text:Example 3: Initially block A has a speed of 3 m/s as shown. Determine the speed of block B at t = 6 s. The coefficient of kinetic friction between block A and the surface is Hk = 0.15. The pulleys are weightless and frictionless. 27 M3VB.y'1 +E]° F,dt = „dt = M²VB.y'.2 1 VB.y" A,x +(2T – 20-9.81). 6 = 20 - v3,y' 2 2 1 = 20. 20- •V A,x,2 W
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