Example 3.16: The power output of an adiabatic steam turbine is 5 MW. Determine the work done per unit mass of the steam flowing through the turbine without neglecting the kinetic and potential energies. Also, calculate the mass flow rate of the steam. Answer: w=872.48 kJ/kg, m '=8.73 kg/s P = 2 MPa T = 400°C V = 50 m/s 21 = 10 m Property Unit Inlet Oulet MPa/kPa 15 V m/s 50 180 m 10 6 T °C 400 STEAM -- 90% TURBINE X -- Wout = 5 MW P2 = 15 kPa X2 = 90% V2 = 180 m/s Z = 6 m

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Example 3.16: The power output of an
adiabatic steam turbine is 5 MW. Determine
the work done per unit mass of the steam
flowing through the turbine without
neglecting the kinetic and potential
energies. Also, calculate the mass flow rate
of the steam. Answer: w=872.48 kJ/kg, m
'=8.73 kg/s
P= 2 MPa
T = 400°C
V = 50 m/s
Z1 = 10 m
Property
Unit
Inlet
Oulet
MPa/kPa
15
V
m/s
50
180
10
6
°C
400
STEAM
90%
TURBINE
X
W = 5 MW
P2 = 15 kPa
X2 90%
V2 = 180 m/s
22 = 6 m
Transcribed Image Text:Example 3.16: The power output of an adiabatic steam turbine is 5 MW. Determine the work done per unit mass of the steam flowing through the turbine without neglecting the kinetic and potential energies. Also, calculate the mass flow rate of the steam. Answer: w=872.48 kJ/kg, m '=8.73 kg/s P= 2 MPa T = 400°C V = 50 m/s Z1 = 10 m Property Unit Inlet Oulet MPa/kPa 15 V m/s 50 180 10 6 °C 400 STEAM 90% TURBINE X W = 5 MW P2 = 15 kPa X2 90% V2 = 180 m/s 22 = 6 m
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