Example 8.5, pg. 262 Ammonia, NH3, can be synthesized by this reaction: 2 NO(g) + 5 H2(g) 2 NH3(g) + 2 H,0(g) - What maximum amount of ammonia in grams can be synthesized from 45.8 g of NO and 12.4 g of H2?
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- The sex attractant of the common housefly is a hydrocarbon named muscalure, C23H46. On treatment of the muscalure with aqueous acidic KMnO4, two products are obtained, CH3(CH2)12CO2H and CH3(CH2)7CO2H. Propose a structure for the muscalure. Please provide a full explanation with steps when providing the structure as a response, thank you!In the following cases rearrange the compounds as directed : (Delhi 2010)(i) In an increasing order of basic strength :C6H5NH2, C6H5 N(CH3)2, (C2H5)2NH and CH3NH2(ii) In a decreasing order of basic strength :Aniline, p-nitroaniline and p-toluidine(iii) In an increasing order of pKb values :C2H5NH2, C6H5 NHCH3, (C2H5)2NH and C6H5NH2[Rh(PPh3)3Cl] is a precatalyst that can be activated by dissociation of a phosphine ligand to form an active catalyst, B, which is used in the hydrogenation of alkenes. The active catalyst can then undergo oxidative addition in the presence of H2 to form complex C. Propene coordinates to C to form complex D, which then undergoes a 1,2- insertion step to form E. Reductive elimination of propane from E regenerates the active catalyst B. Draw complexes B – E and hence provide a full catalytic cycle, including the activation step, for the hydrogenation of propene
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