Example 8-17 depicts the following scenario. A block of mass m1 = 2.40 kg is connected to a second block of mass m2 = 1.80 kg, as shown in the figure. When the blocks are released from rest, they move through a distance d = 0.500 m, at which point m2 hits the floor. If the coefficient of kinetic friction between mj and the horizontal surface is Luk = 0.450, the speed of the blocks just before m2 lands is 1.30 m/s.

College Physics
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Chapter7: Rotational Motion And The Law Of Gravity
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Find the required coefficient of kinetic friction for a landing speed of 1.70m/s.

Example 8-17 depicts the following scenario. A block of mass m1 = 2.40 kg is connected to a second block of mass m2 = 1.80 kg, as shown in the figure. When the blocks are
released from rest, they move through a distance d = 0.500 m, at which point m2 hits the floor. If the coefficient of kinetic friction between mj and the horizontal surface is
Luk = 0.450, the speed of the blocks just before m2 lands is 1.30 m/s.
Transcribed Image Text:Example 8-17 depicts the following scenario. A block of mass m1 = 2.40 kg is connected to a second block of mass m2 = 1.80 kg, as shown in the figure. When the blocks are released from rest, they move through a distance d = 0.500 m, at which point m2 hits the floor. If the coefficient of kinetic friction between mj and the horizontal surface is Luk = 0.450, the speed of the blocks just before m2 lands is 1.30 m/s.
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