HELLO SIR, COULD YOUSOLVE THIS TABLE TOPICABOUT STRENGTH OFMATERIALS LABORATORY?BENDING TESTSECOND STAGEExample: Copper MaterialDistance between anchor= 100 mmL = Imh = 6.5mm, b = 25.5 mmI= bh/12 = 583.6 mmY = h/2 = 6.5/2MassMoment02 (N/m)=1/R(m)5.463*10 14.008*1010 1.04*10F (N)R (m)E (N/m?)No.(gm)(N.m)(mm)1000.9810.09810.13961.23822001.9620.19620.38328.94710.926*10 11.06 *10103.3000.5344000,75001.076001.2977001.498001.799001.891010002.165. CALCULATIONWhere:M- MomentI- Area Moment of Inertia (kg/m?)--b xh (m*)12o-Stress (MPA)yc= Thiekness h/2 (mm)E- Young's ModulusR- Radius of Curvature (mm)If an arm is subjected to a bending moment, we can use Equation (1) to calculate(bending stress, bending amount, bend radius of the bar, modulus of elasticity ofthe bar material). By knowing the magnitude of the effective moment (M) and themoment of inertia of the rod section (I), and in the given case in the experiment,the radius of the rod curve (R) can be caleulated with an acceptable approximationaccording to the following figure:RR-8L/2From the above triangle and according to Pythagoras law:R'-+ (R-8). .2L+ R -2x8 x R+ 8..3While & is a small number, then; we can neglect (8) from other side and theequation will be come:L2x Rx8 =.4R- L8x8Now as we can calculate (I, M, R) then we can also calculate Young's Modulus forthe material.By return to Equation (1) we find that:Exyo, -R.7The value of (6) resulting from the two equations (6 and 7) proves the validity ofthe equation (1).

Answered: Image /qna-images/answer/94136aec-5221-4d96-a42e-13a3ea1e24e1.jpg

HELLO SIR, COULD YOU SOLVE THIS TABLE TOPIC ABOUT STRENGTH OF MATERIALS LABORATORY ?BENDING TEST SECOND STAGE Example: Copper Material Distance between anchor= 100 mm L= Im h = 6.5mm, b = 25.5 mm I= bh/12 = 583.6 mm* Y = h/2 = 6.5/2

HELLO SIR, COULD YOU SOLVE THIS TABLE TOPIC ABOUT STRENGTH OF MATERIALS LABORATORY ?BENDING TEST SECOND STAGE Example: Copper Material Distance between anchor= 100 mm L= Im h = 6.5mm, b = 25.5 mm I= bh/12 = 583.6 mm* Y = h/2 = 6.5/2

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Find the equivalent stresses at Points 1 and 2 of the element with given geometry and loading conditions according to the Maximum shear stress hypothesis and the Maximum strain energy hypothesis. Shaft diameter: 20 mm, Shaft Length 120 mm, F1 = 750N, F2 = 3000N, Mb = 2400 N.mm. Steel if St37 and Safety coefficient is 2 If taken, will this stick work safely under these operating conditions? (Yield of given steel Strength 225 Mpa, Tensile strength 370 Mpa)
Explain the most critical loading condition for fuselage central part structure of airliner aircraft. Draw figures of structure elements to resist this loading.
Discuss the concept of shear force and bending moment diagram and its applications Discuss in details the concept of Torsional shear stress and its applications
A windmill turns a series of slender rods fixed about one end (see formula below). They are initially 2 meters long, and go at a speed of 15 rpm. I suggested making the blades 1m long to reduce the cross-sectional area of the windmill, keeping the mass the same for mechanical stress consistency. How fast are the windmill blades going now, in revolutions per minute?
STRENGTH OF MATERIALS (Please write the complete solutions and FBDs completetely and correctly. No long explanation needed.Thumbs up will be given) A loaded beam, 60 mm wide by 200 mm high and 8 in long, has the shear and moment diagrams as shown below. (a) Determine the magnitude, type and location of the maximum flexural stress (b) Determine the type and magnitude of stress in a fiber 40 mm from the top of the beam at a section 2.5 m from the left end, Express final answers in MPa. (Use I=bh3/12
Write a short explanation for the following terms: 1. Strain 2. Young's Modulus of Elasticity 3. Design Limit Load & Design Ultimate load 4. Safe-life 5. Fail-safe structure 6. Fatigue 7. Loads on fuselage
A part is loaded with a combination of bending, axial, and torsion such that the following stresses are created at a particular location:Bending: Completely reversed, with a maximum stress of 60 MPaAxial: Constant stress of 20 MPaTorsion: Repeated load, varying from 0 MPa to 70 MPaAssume the varying stresses are in phase with each other. The part contains a notch such that Kf,bending = 1.4, Kf,axial = 1.1, and Kf,torsion = 2.0. The material properties are Sy = 300 MPa and Su = 400 MPa. The completely adjusted endurance limit is found to be Se = 160 MPa. Find the factor of safety for fatigue based on infinite life, using the Goodman criteria. If the life is not infinite, estimate the number of cycles, using the Walker criterion to find the equivalent completely reversed stress. Be sure to check for yielding.
Please show a clear step-by-step solution. Thank you! What is the proportion of the alteration in length for Spring A to Spring B, supposing that both springs carry an equal amount of load? Springs A and B have the identical qualities, with the exception that Spring A has 12 times the number of turns as Spring B.
K=17 so 107 MPa strength of material question.
You are given a square rod of 6061-T6 aluminum (cross-section = 4mm X 4mm, length = 2.3m). The material has a Young’s modulus of 72 GPa. If a compressive load of 3 kN is applied parallel to the 2.3m dimension, what is the resulting engineering normal strain?
Define the term absolute maximum shear stress in the material?
A steel rotating-beam test specimen has an ultimate strength of 1600 MPa. Estimate the life of the specimenif it is tested at a completely reversed stress amplitude of 900 MPa.