Explain what ll means in the Zeq equation? How do you solve the equation examples(Aug22)↓2 of 3capacitor.ANS:Vc =#Vs3R₁3E+1Vc$FZcZcR1 + Zc + ZeqR}ZLwwWhere Zeq = (R2+Z₁) || R3 = (4 + j2) 2Vc = (-0.12- j 1.7) = 1.71-94° voltsVs%5R₂T+ Automatic Zoom6R3Y&7R₁1022, R2 = 552,R3 =1092, Zc = -j 2,ZL=j5QVs = 24/0° volts* 0081(9O

Answered: Image /qna-images/answer/9816fa12-91f6-4fe5-aa9e-b87af2cf04f5.jpg

examples(Aug22) 2 of 3 capacitor. ↓ Vs R₁3 ANS: Vc = ww +1 Vc F Zc Zc R1 + Zc + Zeq V }ZL Vs R₂ -+ Automatic Zoom R3 Where Zeq = (R₂+Z₁) || R3 = ( 4 + j2) Vc = (-0.12- j 1.7) = 1.71-94° volts R1 1022, R2 = 5, R3 =1092, Zc = -j 2, ZL=j5Q Vs = 24/0° volts

examples(Aug22) 2 of 3 capacitor. ↓ Vs R₁3 ANS: Vc = ww +1 Vc F Zc Zc R1 + Zc + Zeq V }ZL Vs R₂ -+ Automatic Zoom R3 Where Zeq = (R₂+Z₁) || R3 = ( 4 + j2) Vc = (-0.12- j 1.7) = 1.71-94° volts R1 1022, R2 = 5, R3 =1092, Zc = -j 2, ZL=j5Q Vs = 24/0° volts

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.17MCQ: Consider the load convention that is used for the RLC elements shown in Figure 2.2 of the text. A....

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Concept explainers

Latches and Flip Flop

Just like logic gates, the latches and flip-flops are the important elements of an electronic circuit. The logic gates form the important part of combinatorial circuits, while the latches and flip-flops form the essential part of a sequential circuit. Sequential circuits form the important concept of automata theory in electronics and electrical engineering, these circuits are a kind of logic circuit whose output depends on both present input and past inputs, that is, the input history.

Question

100%

Explain what ll means in the Zeq equation? How do you solve the equation

examples(Aug22)
↓
2 of 3
capacitor.
ANS:
Vc =
#
Vs
3
R₁3
E
+1
Vc
$
F
Zc
Zc
R1 + Zc + Zeq
R
}ZL
ww
Where Zeq = (R2+Z₁) || R3 = (4 + j2) 2
Vc = (-0.12- j 1.7) = 1.71-94° volts
Vs
%
5
R₂
T
+ Automatic Zoom
6
R3
Y
&
7
R₁
1022, R2 = 552,
R3 =1092, Zc = -j 2,
ZL=j5Q
Vs = 24/0° volts
* 00
8
1
(
9
O

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