Exercise 2: Write, compile and execute the program below. Explain why the function swap does not work properly. Using pointers, change the program to make the function swap to work properly. Code: #include #include void swap (int a, int b); int main() int c = 10, d = 25; printf("\nBefore calling the function swap, c=%d and d=%d", c, d); Swap (c, d); printf("\nAfter calling the function swap, c=%d and d=%d\n", c, d); return 0; void swap(int a, int b) { int temp; temp - a; a = b; temp;
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- 1. Inspect the code and in your own interpretation, describe the reason call to functionChangeIt_1(n) will not change x in main()? 2. Inspect the code and in your own interpretation, describe the reason parameter n inChangeIt_2(int *n) is a pointer, and statement in the function is *n = 6 ? 3. Write a function called void swap with two parameters, which will receive the addressof x and y as pointer. The function should swap the value of x and y only if x is larger thany. Print the value of x and y after the function call. 4. Write a function called double getAverage(int *array, int SIZE), whereit accept the array as pointer, and return the average of the array. Print the returnedvalue from this function. Always use *array rather than subscript to access the arrayvalue.The following is the difference between void and NULL pointers: Use relevant examples to back up your statement.For C++, How would I call or use a function that is passed by pointer or a reference? How would I use these in this example below? I understand how passing by value works, but when it comes to passing by references and pointers, that is when I get confused. #include <iostream> using namespace std; // passing by reference in this function void pass_ref(int &ref); // passing by pointer in this function void pass_ptr(int* ptr);
- Please help me make memory diagrams for points one, two and three in the program. I dont know how to do so and I need to understand, also please explain what youre doing as youre solving /* An exercise to help you understand the use of pointer variables. */ #include <stdio.h> int main(void){ int foo; int bar; int *fred; int *sam; bar = 100; foo = 200; fred = &foo; /* point one */ printf("point one: foo is %d and bar is %d.\n", foo, bar); sam = &bar; *sam += 30; *fred -= 40; /* point two */ printf("point two: foo is %d and bar is %d.\n", foo, bar); fred = &bar; *fred += 5; /* point three */ printf("point three: foo is %d and bar is %d.\n", foo, bar); printf("point three: *fred is %d and *sam is %d.\n", *fred, *sam); sam = &foo; *sam = *fred; /* point four */ printf("point four: foo is %d and bar is %d.\n", foo, bar); *sam *= 100; sam = fred; /* point five */ printf("point five: foo is %d and bar is %d.\n", foo, bar);…The following describes the difference between void and NULL pointers: Make proper use of examples to bolster your argument.Finish the swap function below using pointers and write the call to swap in the reverse function using the address of the array positions array[i] and array[size-i-1].using pointers. DON'T FORGET TO DECLARE THE PARAMETERS in the function. (Hint: if you can't figure it out with pointers, do it with the references #include <iostream>using namespace std; // Function to swap two ints using pointers// @param pointer to an int// @param pointer to an intvoid swap( ) {// TODO: Add code that swaps two integers using pointers } // Function to reverse arrayvoid reverse(int a[], int size) {for (int i = 0; i < size/2; i++) {// TODO: write the call to swap in the reverse function using the // address of the array positions array[i] and array[size-i-1].
- in C Given the code below, what would be the proper way to pass the pointers ptr_1, and ptr_2, to the function mix () defined below? #include <stdio.h> void mix( float *, float * ); int main (void) { float *ptr_1, *ptr_2; mix( ?, ? ) <--- What is the correct way to call the function mix (), and pass the pointer variables ptr_1, ptr_2? return 0; }Explain the different between a pointer variable and other variables such as int, float, char. You can draw a specific diagram to make your explanation clearer.1: This program demonstrates the use of pointers. What is the output of this program? Assume we know that the initial address of x is 0012FF44. #include <iostream> using namespace std; int main() { int x=25; int *ptr; // pointer ptr=&x; cout<<x<<endl; cout<<*ptr<<endl; cout<<ptr<<endl; //Now we assign 100 to x *ptr=100; cout<<endl; cout<<"Now we assign 100 to x:"<<endl; cout<<x<<endl; cout<<*ptr<<endl; cout<<ptr<<endl; return 0; } Write down the output:
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