Exercise Consider the following potentiometric titration data for acetic acid solution against sodium hydroxide solution. Use the following data to: (a) Plot the pH of solution vs. Volume of NaOH (VNaOH)added using the guidelines stated earlier in the session (b) Calculate the first derivative of the titration curve of CH3COOH (c) Plot the first derivative of pH vs. VNaOH, and determine the end point of titration PH AV APH first derivative= VSOH (mL) 0.0 2.0 4.0 10.0 = 12.0 14.0 15.0 15.5 15.6 15.7 15.8 16.0 17.0 18.0 20.0 24.0 Endpoint = 15.62 ml Endpoint = 15.20 ml Endpoint = 15.66 ml CH3COOH(aq) + NaOH(aq) → CH3COONa (aq) + H₂O(l) Endpoint 15.50 ml 2.89 4.52 5.06 5.89 6.15 6.63 7.08 7.75 8.40 9.29 10.07 10.65 11.34 11.63 12.00 12.41 АРН ΔΙ'

Appl Of Ms Excel In Analytical Chemistry
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Chapter8: Polyfunctional Acids And Bases
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Exercise Consider the following potentiometric titration data for acetic acid solution
against sodium hydroxide solution.
Use the following data to:
(a) Plot the pH of solution vs. Volume of NaOH (VNaOH)added using the guidelines stated
earlier in the session
(b) Calculate the first derivative of the titration curve of CH3COOH
(c) Plot the first derivative of pH vs. VNaOH, and determine the end point of titration
pH
AV APH
first derivative=
VN₂OH
(mL)
0.0
2.0
4.0
10.0
12.0
14.0
15.0
15.5
15.6
15.7
15.8
16.0
17.0
18.0
CH3COOH(aq) + NaOH(aq) → CH3COONa* (aq) + H₂O(1)
20.0
24.0
Endpoint = 15.62 ml
Endpoint = 15.20 ml
Endpoint = 15.66 ml
Endpoint = 15.50 ml
2.89
4.52
5.06
5.89
6.15
6.63
7.08
7.75
8.40
9.29
10.07
10.65
11.34
11.63
12.00
12.41
ApH
ΔΙ
Transcribed Image Text:Exercise Consider the following potentiometric titration data for acetic acid solution against sodium hydroxide solution. Use the following data to: (a) Plot the pH of solution vs. Volume of NaOH (VNaOH)added using the guidelines stated earlier in the session (b) Calculate the first derivative of the titration curve of CH3COOH (c) Plot the first derivative of pH vs. VNaOH, and determine the end point of titration pH AV APH first derivative= VN₂OH (mL) 0.0 2.0 4.0 10.0 12.0 14.0 15.0 15.5 15.6 15.7 15.8 16.0 17.0 18.0 CH3COOH(aq) + NaOH(aq) → CH3COONa* (aq) + H₂O(1) 20.0 24.0 Endpoint = 15.62 ml Endpoint = 15.20 ml Endpoint = 15.66 ml Endpoint = 15.50 ml 2.89 4.52 5.06 5.89 6.15 6.63 7.08 7.75 8.40 9.29 10.07 10.65 11.34 11.63 12.00 12.41 ApH ΔΙ
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