Exercise 1: Draw the shear and bending-moment diagram for girder AB. Also determine the maximum bending-moment.Where x = 2020100214Note: Solve the exercise #1 problem with the same way and steps on how the sample problem #3 was solved. Exercise No. 1: Draw the shear and bending moment diagrams for girder AB. Alsodetermine the maximum bending-moment.2mP₁Į2mP₂4mP3X4th to the last digit3rd to the last digit2nd to the last digitLast digit6m4mP3L=20 mParameter = a + (b-a)x/10where : x = student's ID digit numberParameterP₁P₂P3P44ma455565756mPab50607080P₁4mUnitsKNKNkNKN2mP₂2mBd SHEAR and MOMENT DIAGRAMS in BEAMSSample Problem No. 3: Draw the shear and bending moment diagrams for beam AB.Also determine the maximum bending-moment. All pulleys have a 600 mm diameter.AxStep 1: Draw the free body diagramAAx = 50Ay50 kN3m45.78Ay = 45.7850 kNStep 3: Forces Diagram3m3m1ml-4.22C7m187.3450137.347mStep 4: Shear and moment diagrams50Step 2: Compute the reactions at the supportΣΕ= 0 ; - Ax + 50 = 0; Ax= 50 kNΣM₁ = 0; 50(3-.300)-50(1+. 300) - By(16.6) = 0 ; By = 4.22 kN78 KN↑ΣF, = 0; Ay+By-50=0; Ay= 45.78 KN7m-54.220.6m500.6m0.6m1m!1m157.81mÝ...75.325.31m1m6m50 kNStep 5: Determine the maximum bending moment:Therefore: Max. Moment=187.34 kN-m occur at point b.6mThere are moments at c, d and e. M = 50 kN (1m) = 50 kN -mMc = 50 kN-m clockwise ; Md and Me = 50 kN-m counter clockwise6m50ByBB-4.22By = 4.22

Answered: Image /qna-images/answer/04887951-1229-4001-8ba3-625e613c5959.jpg

Exercise No. 1: Draw the shear and bending moment diagrams for girder AB. Also determine the maximum bending-moment. 2m P₁ ↓ 2m P₂ 4m P3 x 4th to the last digit 3rd to the last digit 2nd to the last digit Last digit 6m 4m P3 L=20 m Parameter = a + (b-a)x/10 where : x = student's ID digit number Parameter P₁ P₂ P3 P₁ 4m a 45 55 65 75 6m Pa b 50 60 70 80 P₁ 4m Units kN KN KN KN 2m P₂ 2m B d

Exercise No. 1: Draw the shear and bending moment diagrams for girder AB. Also determine the maximum bending-moment. 2m P₁ ↓ 2m P₂ 4m P3 x 4th to the last digit 3rd to the last digit 2nd to the last digit Last digit 6m 4m P3 L=20 m Parameter = a + (b-a)x/10 where : x = student's ID digit number Parameter P₁ P₂ P3 P₁ 4m a 45 55 65 75 6m Pa b 50 60 70 80 P₁ 4m Units kN KN KN KN 2m P₂ 2m B d

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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