Answered: Experiment Number Initial Rate (M/s)…

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter32: Radiochemical Methods

Section: Chapter Questions

Problem 32.12QAP

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NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,k
Explain 4 traditional techniques half life method , isolation method , differential method and isolation method in chemical kinetics?
0% 25% 50% 75% 100% Depth of H2O2 Solution (d) 2.1 cm 2.1 cm 2.1 cm 2.1 cm 2.1 cm Trial 1 Time 180 sec 84.61 sec 43.52 sec 36.90sec 25.90 sec Trial 2 Time 180 sec 92.25 sec 38.16 sec 34.36 sec 23.57sec Trial 3 Time 32.53 sec 18.82 sec Average Time (t) 180 sec 88.43 sec 40.84 Sec 34.5 sec 22.76 sec Rate of the Reaction(R = d/t) 0.012 cm/sec 0.02 cm/sec 0.051 cm/sec 0.061 cm/sec 0.0923cm/sec , graph rate of reaction on the y-axis and percent concentration of enzyme on the x-axis. If the points are linear, draw a “best-fit” straight line through or near all of the data points. Based on the information in the data table and your graph, explain the relationship between percent concentration of catalase and rate of reaction. Did your actual results match your hypotheses? If not, why?
The first-order degradation rate constant k was determined to be 0.0125/day for contaminant A and 0.0030/day for contaminant B in a soil. Calculate the half-life T1/2 and the 95% dissipation time for these contaminants in the soil. Compare the persistence between the two contaminants.
the background for the experiment (=mechanism) 2 paragraphs
Table 2: Molarity of H2O2 and KI and Reaction Rate Trial H2O2 Concentration, M KI Concentration, M Reaction Rate(Reciprocal Slope) 1 0.29 M 0.40 M 14.08 2 0.29 M 0.20M 25 3 0.023 M 0.40 M 20 please help me with this part Rate constant value Trial 1 ______________ Trial 2 ______________ Trial 3 ______________ Average _____________
If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)
Choices for slope: a. -1.35 x 10^4 b. 1.35 x 10^4 c. -1.09 x 10^4 d. 1.09 x 10^4 choices for y intercept: a. -27.8 b. 27.8 c. 37.4 d. -37.4 choices for pearson: a. -0.962 b. -1000 c. -0.982 activation energy a. 9.06 x 10^4 b. 113 c. 90.65 collision frequency factor A a. 1.15 x 10^12 b. 113 c. 90.65
Faat pls i will give u like for sure solve this question correctly in 5 min pls
Example: A GC-FID analysis was conducted on a soil sample containing pollutant X. The following separations were conducted: t (minutes) peak area Injection 1 21.1 ppm Toluene internal Standard 10.11 36,242 33.4 ppm 14.82 45,997 Injection 2 21.1 ppm Toluene Internal Standard 10.05 38,774 unknown concentration X 14.77 39,115 What is the concentration of X in the sample?
If the enzyme lactase has a Vo of 0.111111111111 mM per minute when [S] = 1.0 mM, and a Vo of 0.20 mM per minute when [S] = 5.0 mM, what is its Km? Calculate Vmax of the above enzyme (lactase). Calculate the slope on a Lineweaver-Burk plot (Km/Kmax) for the above enzyme (lactase).
y= mx+ b Slope () = -4E-09 y-intercept () = 0.4021 and OD= 0.540 , Calculate the concentration (x)

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Experiment Number Initial Rate (M/s) [A](M) [B](M) 4.0 x 10-5 4.0 x 10-5 16.0 x 10-5 0.100 0.100 0.100 0.200 3 0.200 0.100 2. 3.