Explain what it means to say that lim f(x) = 3 and lim f(x) = 8. x-9- O As x approaches 9, f(x) approaches 8, but f(9) = 3. O As x approaches 9, f(x) approaches 3, but f(9) = 8. O As x approaches 9 from the right, f(x) approaches 3. AS x approaches 9 from the left, (x) approaches 8. O As x approaches 9 from the left, f(x) approaches 3. As x approaches 9 from the right, f(x) approaches 8. In this situation is it possible that lim f(x) exists? Explain. O Yes, f(x) could have a hole at (9, 3) and be defined such that f(9) = 8. O Yes, f(x) could have a hole at (9, 8) and be defined such that f(9) = 3. O Yes, if f(x) has a vertical asymptote at x = 9, it can be defined such that lim f(x) = 3, lim f(x) = 8, and lim f(x) exists. xー9 xー9 O No, lim f(x) cannot exist if lim f(x) = lim f(x).

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