Explain why each of the following integrals is improper. 9. (a) dx Is (x - 6)6 Since y= has a vertical asymptote at x=6, the integral is improper. (x – 6)6 Since y=- has a vertical asymptote at x=5, the integral is improper. (x – 6)6 Since the integral has an infinite interval of integration, the integral is improper. The integral is not improper. 8. (b) 7In(x) dx The integral is not improper. Since the integral has an infinite interval of integration, the integral is improper. Since y=In(x) has a vertical asymptote at x=1, the integral is improper. Since y=In(x) has a vertical asymptote at x=0, the integral is improper. T/4 (c) sec(x) dx Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. Since the integral has an infinite interval of integration, the integral is improper. The integral is not improper. Since y=sec(x) has a vertical asymptote at x=0, the integral is improper.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Explain why each of the following integrals is improper.
9.
(a)
dx
6)6
Since y=-
has a vertical asymptote at x=6, the integral is improper.
(x – 6)6
Since y=-
has a vertical asymptote at x=5, the integral is improper.
(x – 6)6
-
Since the integral has an infinite interval of integration, the integral is improper.
The integral is not improper.
(b)
7ln(x) dx
The integral is not improper.
Since the integral has an infinite interval of integration, the integral is improper.
Since y=In(x) has a vertical asymptote at x=1, the integral is improper.
Since y=In(x) has a vertical asymptote at x=0, the integral is improper.
(c)
sec(x) dx
Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper.
Since the integral has an infinite interval of integration, the integral is improper.
The integral is not improper.
Since y=sec(x) has a vertical asymptote at x=0, the integral is improper.
Transcribed Image Text:Explain why each of the following integrals is improper. 9. (a) dx 6)6 Since y=- has a vertical asymptote at x=6, the integral is improper. (x – 6)6 Since y=- has a vertical asymptote at x=5, the integral is improper. (x – 6)6 - Since the integral has an infinite interval of integration, the integral is improper. The integral is not improper. (b) 7ln(x) dx The integral is not improper. Since the integral has an infinite interval of integration, the integral is improper. Since y=In(x) has a vertical asymptote at x=1, the integral is improper. Since y=In(x) has a vertical asymptote at x=0, the integral is improper. (c) sec(x) dx Since y=sec(x) has a vertical asymptote at x=-4, the integral is improper. Since the integral has an infinite interval of integration, the integral is improper. The integral is not improper. Since y=sec(x) has a vertical asymptote at x=0, the integral is improper.
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