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A: Translate the following chemical reaction into english words using no symbols : 4NH3 + 5O2 --->…
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Explain why the product distribution is observed for the following reactions:
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- Compounds Mass 3-nitrophthalic acid used 200 mg = 0.2g 8% aqueous hydrazine used 0.4mL 3-nitrophthalhydrazide obtained 130 mg = 0.13 g sodium hydrosulfite dihydrate 0.6 g luminol obtained 70 mg = 0.07 g compute yield for nitrophthalhydrazide in the first step (assume nitrophthalic acid is limiting reagent) compute yield for luminol in the second step (using nitrophthalhydrazide as limiting reagent) compute yield for the overall reactionNa2SO3Na2SO3 reacts with HClO4HClO4 according to the reaction Na2SO3(aq)+2HClO4(aq)⟶2NaClO4(aq)+H2O(l)+SO2(g)Na2SO3(aq)+2HClO4(aq)⟶2NaClO4(aq)+H2O(l)+SO2(g) You wish to provide a 50% excess of 6.466.46 wt% aqueous HClO4HClO4 to react with 50.050.0 mL of 0.07040.0704 M Na2SO3Na2SO3. Calculate the mass of the 6.466.46 wt% aqueous HClO4HClO4 solution required to provide the 50% excess.Weight of crude acetanilide = 2.2 grams Weight of pure acetanilide = 1.5 grams Melting point of recrystallized acetanilide = 114.3 C (a) What is the % yield? (b) What is the % purity?
- The oxidizing and reducing agent is: A) Sodium benzoate B) Sodium nitrite C) Sodium thiosulfate D) Sodium bicarbonate E) Sodium chlorideGive the balanced equation of acetylene and the following reactions • Combustion • dilute KMnO4 • Ammoniacal CuCl / Ammonical AgNO3Give reactants and explain selectivity
- a reaction was preformed in which 0.550 mL of p-anisaldehyde was reacted with a slight excess of benzyltriphenylphosphonium chloride to make 0.646 g of p-methyoxystilbene. calculate the theoretical yield and percent yield for this reaction. 388.9 g/mol benyzyltriphenylphosphonium chloride 136.2 g/mol anisaldehyde d= 1.12 g/mL 210.1 g/mol p-methoxystilbeneWhich one of the following compounds produces 3 M solution when 1 mole of compound is dissolved in 1 L of solution? A. H2SO3 B. Hg2Br2 C. Ag2SO4 D. Cu2S E. SrCl2when 2.0 of NaOHCO3 was heated the weight of the reside product after heating was 1.0g calculate the percent weight loss on heating
- Some people have an allergic reaction to the food preservative sulfite (SO32−). Sulfite in wine was measured by the following procedure: To 50.0 mL of wine were added 5.00 mL of solution containing (0.8043 g KIO3 + 5 g KI)/100 mL. Acidification with 1.0 mL of 6.0 M H2SO4 quantitatively converted IO3− into I3−. The I3− reacted with SO32− to generate SO42−, leaving excess I3− in solution. The excess I3− required 12.86 mL of 0.04818 M Na2S2O3 to reach a starch end point. lO_3^- + 8l^- + 6H^+ rightarrow 3l_3^- + 3H_2O l_3^- + SO_3^2 - + H_2O rightarrow 3l^- + SO_4^2- + 2H^+ l_3^- + 2S_2O_3^2- rightarrow 3l^- + S_4O_6^2- Find the concentration of sulfite in the wine. Express your answer in mol/L and in mg SO32− per liter._____mol/L HINTS: Don't use scientific notation, do put zero before decimal point, carefully evaluate significant figures.The density of acetic anhydride (C4H6O3) is 1.08 g/mL. Calculate the moles of acetic anhydride present in 3.60 mL of acetic anhydride.Calculate the moles of the limiting reagent for the following reaction: oxidation of cyclododecanol to cyclododecanone. 0.2093 grams of Cyclododecanol 0.5 mL of acetone 0.20 mL of Glacial acetic acid 2.0 mL of bleach Final weight of cyclododecanone = 0.0578 g