Express the equilibrium constant for the following reaction. 16 CH3Cl(g) + 8 Cl2(g) ⇔ 16 CH2Cl2(g) + 8 H2(g) (CH3C1]!/2{Cl2]K(CH2C12]1/2[H2][CH2C12][H2][CH3C1][Cl2]%3D[CH2C12]16H2 SK =[CH3C1]16¶C12]8[CH3C1]16C12}8K =[CH2Cl2]16H21$[CH3CI][Cl2]K=[CH2C12][H2]%3D

the equilibrium constant expression can be written as the ratio of the concentration of the…

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Express the equilibrium constant for the following reaction. 16 CH3Cl(g) + 8 Cl2(g) ⇔ 16 CH2Cl2(g) + 8 H2(g)

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL2: Mass Spectrometry

Section: Chapter Questions

Problem 20CTQ

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Question

Express the equilibrium constant for the following reaction.

16 CH₃Cl(g) + 8 Cl₂(g) ⇔ 16 CH₂Cl₂(g) + 8 H_2(g)

(CH3C1]!/2{Cl2]
K
(CH2C12]1/2[H2]
[CH2C12][H2]
[CH3C1][Cl2]
%3D
[CH2C12]16H2 S
K =
[CH3C1]16¶C12]8
[CH3C1]16C12}8
K =
[CH2Cl2]16H21$
[CH3CI][Cl2]
K=
[CH2C12][H2]
%3D

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