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- Topic: Couples, Resultant of Force Systems & Equilibrium If F1 = 10N, F2 = 15N, F3 = 8N, F4 = 10N, F5 = 18N, and the length of te side of a red square is 1m. Calculate magnltude (+ for CCW, - for CW) of the resuItant moment (N-m) about point A. Calculate the magnitude of the reItant f0rce (N). (Answer: 50.80Nm, 20.33N)PROBLEM 4: The boom OC is subjected to tension forces at A and C. It is known that the tension in A is 26 kN and at C is 12 kN. Unit vector CE. (ANSWER: -0.38i-0.87j+0.32k) Tension at A. (ANSWER: 13.20i-15.8j+15.8k kN VECTOR COMPONENT FORM) Moment about O due to the given forces. (ANSWER: 78.71i+0j+3.2k kN VECTOR COMPONENT FORM)Q1-Consider the below hip joint prosthesis. When standing symmetrically on both feet, a joint reaction force of F =350N is acting at the femoral head (point A) due to the body weight of the patient. The geometric parameters of the prosthesis are l1= 30 mm, l2= 40 mm, θ1= 35°, θ2= 100°. Determine the moments generated by force F about points C on the prosthesis when force F applies along line AB.
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is given as γ=8°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=50°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N)b) Find the tensile force T2 in cable 2. (Write your result in N)c) Find the angle α of cable 1 with the horizontal.can you pls help me solve this as for my understanding.. I am trying to answer exercises. subject: Statics •PLS ANSWER WITH COMPLETE SOLUTION •3 DEC PLACES •PROVIDE FREE BODY DIAGRAM (if applicable) •Correct UNITS 4. Determine the moment about the origin O of the force F = 2i + 3j -4k that acts at a point A. Assume that the position vector of A is (a) r = 3i -6j +5k, (b) r = i - 4j - 2k, (c) r = 4i + 6j -8k. Thank you. *I'll give your answer a LIKE for helping me.a = 4 mb = 3.2 mc = 2 mF = {-7i+4j+12k} NSpecified axis: AF Find the magnitude of the moment of F about the specified axis.If the calculated answer is not whole number, express it in 4 significant figures.
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=250 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is γ=6°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=40°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. ResponsePassing an exploratory section through the body and exposing the internal forces acting on the exploratory section, Mxy represents Torsional Moment about x-axis.Rigid arm AB is subject to a downward force F=270 lbf. It is supported by asquare shaft journal bearing at A and a cable BC.A. Draw a clear and large free-body diagram (FBD) to show all reaction components on AB. Ifany are not engaged, cross them out and add the note “N.E.” for “Not Engaged.” You do NOTneed to set up any equations or solve for any of the reactions.B. Find the unit vector for cable BC.
- The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. Responseinclude also the free body diagramThe rigid pipe is subject to the following loads. Neglecting the weight of the pipe, determine the moment at O. SOLVE THE FF Vector component form of 50-lb force (ANSWER: 25.000i +0j -43.30k lb) Magnitude of the resultant force (ANSWER: 78.10 lb) Position vector of the 50-lb force from point O to its point of application on the pipe. (ANSWER: -15i -10j +12k inch) Moment at point O, in vector component form. (ANSWER: 1153.01i -829.52j +250.00k lb-in)