Express your answers numerically using two significant figures separated by commas. Figure < 1 of 1 Hν ΑΣφ I120. Ian. Iısa. Iz20. Izsn = 0.18,0.16,0.19,0.15,- 0.01 22 Q 12Ω ww Submit Previous Answers Request Answer 15 Q X Incorrect; Try Again; 5 attempts remaining 25 Ω 14 Ω Part B 6.0 V What is the direction of I159?

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter27: Direct-current Circuits
Section: Chapter Questions
Problem 15P: Four resistors are connected to a battery as shown in Figure P27.15. (a) Determine the potential...
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Part A
(Figure 1)
Determine the current through each of the resistors in the figure.
Express your answers numerically using two significant figures separated by commas.
Figure
1 of 1 >
Hν ΑΣφ
I12n. I14n. In5n. I20. Isn = 0.18,0.16,0.19,0.15, – 0.01
A
22 Ω
12 2
Submit
Previous Answers Request Answer
15 Ω
X Incorrect; Try Again; 5 attempts remaining
25 Ω
14 2
Part B
6.0 V
What is the direction of I150?
Transcribed Image Text:Part A (Figure 1) Determine the current through each of the resistors in the figure. Express your answers numerically using two significant figures separated by commas. Figure 1 of 1 > Hν ΑΣφ I12n. I14n. In5n. I20. Isn = 0.18,0.16,0.19,0.15, – 0.01 A 22 Ω 12 2 Submit Previous Answers Request Answer 15 Ω X Incorrect; Try Again; 5 attempts remaining 25 Ω 14 2 Part B 6.0 V What is the direction of I150?
Expert Solution
Step 1

According to Kirchhoff's first law

Algebraic sum of current at a junction is always zero.

According to Kirchhoff second law

Sum of voltage in a close loop is always zero.

We can use Kirchhoff's laws to solve the problem 

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