Expression for the inductor current
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Consider the circuit above. The switch has been closed for a very long time before opening at t=0s. Determine the Inductor current (in amperes) right after the switch has been opened, the time constant of the circuit for ?>0 (in ms), and the Expression for the inductor current for ?≥0.
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- Capacitive Circuits Fill in all the missing values. Refer to the formulas that follow. XC=12fCC=12fXCf=12CXc Capacitance XC Frequency 38 F 60 Hz 78.8 400 Hz 250 pF 4.5 k 234 F 10 kHZ 240 50 Hz 10 F 36.8 560 nF 2 MHz 15 k 60 Hz 75 nF 560 470 pF 200 kHz 6.8 k 400 Hz 34 F 450Xd=1.0pu Xd'=0.3pu Xd''=0.2pu T"=0.03sec T'=1secThe signals on the oscilloscope V1(t) and V2(t) are given as V1(t) = 300*sin(120 π *t + 30) , 2 V (t) = A*cos(120 π *t + B) in Figure-1. a) Determine the values of A and B.
- For each of the following, determine the frequency: f = 1/T(a) T = 0.5s(b) T = 100ms(c) 5T = 80µs For a: I got 2Hz For b: I got 10Hz and for c: I got 62.5kHz Can you check if I answer it correct.Calculate the energy and power of the following signals.i. x(t) = 3 + sin(t)ii. x[n] = 2^ u[−n]i1 = 100sin (750t + 45) i2 = 50sin (500t-30) U = 200sin (750t-90) Plot three graphs of current and voltage whose equations are as above? (pi= 3 will be taken, frequencies will be found)