F = (-5i +4j+3k)kN A,
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- PROBLEM 4: The boom OC is subjected to tension forces at A and C. It is known that the tension in A is 26 kN and at C is 12 kN. Unit vector CE. (ANSWER: -0.38i-0.87j+0.32k) Tension at A. (ANSWER: 13.20i-15.8j+15.8k kN VECTOR COMPONENT FORM) Moment about O due to the given forces. (ANSWER: 78.71i+0j+3.2k kN VECTOR COMPONENT FORM)Assign the values of shear force and bending moment to the image bar as a function of the x coordinate. q=20kN/m F=14kN M=12kNm L1=1.2m L2=1.4m L3=1.3m L4=1.5m Minimum value of shear force: Qmin = Maximum value of shear force: Qmax= Use units (kN,m), Do not round the invoices in the intermediate stages, but only the final answer!Use the picture to solve these questions 1-The magnitude of the moment induce by the load about the Line-EF is _____ kN*mm. 2- The direction of the moment induce by the load about the Line-EF is _____ kN*mm. 3- The direction of the moment induce by the load about the Line-CD is _____ kN*mm. 4- The state of the internal force at the mid-point of Member-BD _____ . Enter "1" for "tension". Enter "2" for "compression" Enter "3" for "torsion" Enter "4" for "neither tension, nor compression, nor torsion 5- The state of the internal force at the mid-point of Member-BF _____ . Enter "1" for "tension". Enter "2" for "compression" Enter "3" for "torsion" Enter "4" for "neither tension, nor compression, nor torsion
- The piston of a reciprocating engine exerts a firce of 180 kN on crosshead when the crank is 35 degree (angle beta) past TDC. If the stroke of the piston is 800 mm and the length of the connecting rod is 1.65 m, find, in kN. a) the guide force FG and , b) the firce on the connecting rod Rc .hint: radius AC is 1/2 of the stroke and Angle "phi" may be solved using sine law. Draw FBDA hollow steel crank has an outside diameter of 26 mm and an inside diameter of 21 mm. The load magnitudes are Py = 690 N and Pz = 270 N, and the length dimensions are a = 145 mm, b = 399 mm, and c = 261 mm. Determine the magnitudes of the equivalent forces and the equivalent moments that act at the section that contains point K. (a) Axial force in x direction Px (N (b) Shear force in y direction Vy (N (c) Shear force in z direction Vz (N (d) Torque around x axis Tx (N·m) (e) Bending moment around y axis My (N·m) (f) Bending moment around z axis Mz (N·m) Calculate the section properties for the hollow crank at K. (g) Area A (mm2) (h) Polar moment of inertia J (mm4) (i) Area moment of inertia Iy (and Iz) (mm4) (j) QK (for shear force in y-direction) (mm3) Using the sign conventions, determine the normal and shear stresses that act at K and show these stresses on a stress element. (k) Normal stress in x direction σx(MPa) (l) Normal stress in y direction σy(MPa) (m) Shear stress in x-y…Which of the following has the dimension for force M1L-3 M L -1 T-2 M-1 L1 T 2 M1 L1 T-2
- 24 - In the cage system connection in the figure; Rod forcesS1= 100 kN,S2= 40 kN,S3= - 60 kN,S4= 50 kN,If S5= 80 kN, Calculate the resultant force acting on joint point D.If the vector representation of the resultant force is R= Rx i + Ry j, Rx = ? Note: The (-) sign of the rod force S3 indicates that the force is pressure. A) 42.43B) -36.36C) -12.93D) 3.64E) 36.36A ladder carried by a fire truck is 20.0 m long. The ladder weighs 3400 N and its center of gravity is at its center. The ladder is pivoted at one end (A) about a pin (Fig. ); ignore the friction torque at the pin. The ladder is raised into position by a force applied by a hydraulic piston at C. Point C is 8.0 m from A, and the force F S exerted by the piston makes an angle of 40° with the ladder. What magnitude must F S have to just lift the ladder off the support bracket at B? Start with a free-body diagram of the ladder.Which of the following gives the moment MD about point D of the tensile force TBA exerted by the wire at point B? Note that rB/D = (4i - 6k) m and TBA = (-8i + 6j + 4k) kN and that MD = rB/D x TBA. a. (36.0i + 32.0j + 24.0k) kN-mb. (48.0i + 24.0j + 16.0k) kN-mc. (-36.0i - 32.0j - 24.0k) kN-md. (16.0i - 12.0j -8.0k) kN-m
- Expiremental Method: Force Table F1 - 150N, 30° N of E F2 - 100N, 60° E of S 1) Find the Equilibrant Magnitude and Equilibrant Direction 2) Find Resultant Force Vector Magnitude and %Error 3) Find Resultant Force Vector Direction and %ErrorA 415 kg safe is hanging from the apparatus below. Determine the tension in the cable. Dimension a=1.9 m and dimension b=2.5 m. The mass of the beam is 85 kg. Use g = 10 N/kg. Hint: Take torques about the hinge and use the perpendicular lever arm version of the torque equation (the sin theta version will work but will require more calculation).Solve the force and its direction with Fx=130N, Fy=115N
