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f the mass of the bullet is 12.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50-inch plywood.

f the mass of the bullet is 12.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50-inch plywood.

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
Section: Chapter Questions
Problem 44P: Consider two objects with m1 m2 connected by a light string that passes over a pulley having a...
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Your answer is partially correct. Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is dissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d = 0.850 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of 0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of w = 86.0 rad/s. The angular displacement between holes in the first and second disks is A012 = 0.269 rad, and the angular displacement between the holes in the second and third disks is A023 = 0.286 rad. If the mass of the bullet is 12.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50-inch plywood. (a) Number 271.82 (b) Number i 51.209 Units m/s Units J V
Transcribed Image Text:Your answer is partially correct. Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is dissipated by a 0.500-inch piece of plywood. You construct a device that consists of three disks that are separated by a distance d = 0.850 m and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of 0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of w = 86.0 rad/s. The angular displacement between holes in the first and second disks is A012 = 0.269 rad, and the angular displacement between the holes in the second and third disks is A023 = 0.286 rad. If the mass of the bullet is 12.0 g, find (a) the initial speed of the bullet and (b) the energy dissipated by the 0.50-inch plywood. (a) Number 271.82 (b) Number i 51.209 Units m/s Units J V
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