F2-13. Determine its coordinate direction angles of theforce.45-30°F = 75 lbF2-13F2-14. Express the force as a Cartesian vector.F = 500 N60°60°F2-14F2-15. Express the force as a Cartesian vector.F = 500 N60F2-15F2-16. Express the force as a Cartesian vector.F-50 lb1445F2-16F2-17. Express the force as a Cartesian vector.F = 750 N45%F2-17F2-18. Determine the resultant force acting on the hook.F₁ = 500 lb3045°F₂=800 lbF2-1823

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F2-13. Determine its coordinate direction angles of the force. -30° F = 75 lb

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

F2-13. Determine its coordinate direction angles of the
force.
45
-30°
F = 75 lb
F2-13
F2-14. Express the force as a Cartesian vector.
F = 500 N
60°
60°
F2-14
F2-15. Express the force as a Cartesian vector.
F = 500 N
60
F2-15
F2-16. Express the force as a Cartesian vector.
F-50 lb
1445
F2-16
F2-17. Express the force as a Cartesian vector.
F = 750 N
45%
F2-17
F2-18. Determine the resultant force acting on the hook.
F₁ = 500 lb
30
45°
F₂=800 lb
F2-18
23

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