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False Position Method x³ + 4x² - 10 = 0 (1-2) Task: Just continue the given problem using the method given with solutions af (b) - bf (a) f(b)-f(a) x³ + 4x² - 10 = 0 (1-2) limitation Real Roots: 1.365230013 b 2 2 I 1 2 a 1 1.23157895 C с 1.263157895 1.338827839 f(c) -1.60227438 -0.4303647452

False Position Method x³ + 4x² - 10 = 0 (1-2) Task: Just continue the given problem using the method given with solutions af (b) - bf (a) f(b)-f(a) x³ + 4x² - 10 = 0 (1-2) limitation Real Roots: 1.365230013 b 2 2 I 1 2 a 1 1.23157895 C с 1.263157895 1.338827839 f(c) -1.60227438 -0.4303647452

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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False Position Method I 1 2 x³+4x² 10 = 0 (1-2) Task: Just continue the given problem using the method given with solutions af (b) - bf (a) f(b) - f(a) x³ + 4x² - 10 = 0 (1-2) limitation Real Roots: 1.365230013 b 2 2 a 1 1.23157895 - C = C 1.263157895 1.338827839 f(c) -1.60227438 -0.4303647452
Transcribed Image Text:False Position Method I 1 2 x³+4x² 10 = 0 (1-2) Task: Just continue the given problem using the method given with solutions af (b) - bf (a) f(b) - f(a) x³ + 4x² - 10 = 0 (1-2) limitation Real Roots: 1.365230013 b 2 2 a 1 1.23157895 - C = C 1.263157895 1.338827839 f(c) -1.60227438 -0.4303647452
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