Is this answer correct? Fig. 4 , a 2-in-diameter stream of water strikes a 4-ft-square door which is at an angle of 30° withlirection. The velocity of the water in the stream is 60.0 ft/s and the jet strikes the door at itsity. Neglecting friction, what normal force applied at the edge of the door will maintain30.060.052.0-F.90°300Hinge A3.030.0Fig. 4 Given dataVelocity of jet striking the door is V= 60ft'sDensity of water is p = 62.41lb/ftDiameter of jet is D= 2in =;2=0.167ft12%3DAD Tx0.167Area of pipe jet is A=:-= 0.022ft44Assuming velocity v =V =V,From the momemtum equation, we haveF= pAV?Force in the x-direction is F, = pAV (V cos 30°)F =62.4x0.022 x 60(60×0.866)F, = 4.28 kips (towar ds left)Force in the y- direction is F, = pAV (V sin 30°)F, =62.4x0.022 x 60(60x0.5)F, =2.47 kips (upwards)Resultant reaction isF=F+(F,) =V4.28° + 2.47F = 4.94kips3D%3DNormal thrust of water on the door is given asPAV sin (90°-30°) _ 62.4xx0.022 x 60² × 0.866N=32.2N=132.91bs 0.133 kipsAssuming length of the door as 'L'Taking moment at hinge-A,EM, =0LPxL+Fx-Nx==02P=-4.94 +0.133P=4.78kips (away from the door)

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Fig. 4 , a 2-in-diameter stream of water strikes a 4-ft-square door which is at an angle of 30° with lirection. The velocity of the water in the stream is 60.0 ft/s and the jet strikes the door at its ity. Neglecting friction, what normal force applied at the edge of the door will maintain 30.0, 60.0 52.0 90° 30 Hinge A 3.0 30.0 Fig. 4

Fig. 4 , a 2-in-diameter stream of water strikes a 4-ft-square door which is at an angle of 30° with lirection. The velocity of the water in the stream is 60.0 ft/s and the jet strikes the door at its ity. Neglecting friction, what normal force applied at the edge of the door will maintain 30.0, 60.0 52.0 90° 30 Hinge A 3.0 30.0 Fig. 4

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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