Figure 6.12 shows the one-line diagram of a simple three-bus power system with generators at buses 1 and 3. The magnitude of voltage at bus 1 is adjusted to 1.05 pu. Voltage magnitude at bus 3 is fixed at 1.04 pu with a real power generation of 200 MW. A load consisting of 400 MW and 250 Mvar is taken from bus 2. Line impedances are marked in per unit on a 100 MVA base, and the line charging susceptances are neglected. Obtain the power flow solution by the Gauss-Seidel method including line flows and line losses. 1 2 0.02 + j0.04 400 MW 0.01 + j0.03 0.0125 + j0.025 250 Mvar Slack Bus 3 V = 1.0520° 200 MW | V3 = 1.04 Figure 6.12

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.37P
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Figure 6.12 shows the one-line diagram of a simple three-bus power system with
generators at buses 1 and 3. The magnitude of voltage at bus 1 is adjusted to 1.05
pu. Voltage magnitude at bus 3 is fixed at 1.04 pu with a real power generation
of 200 MW. A load consisting of 400 MW and 250 Mvar is taken from bus 2.
Line impedances are marked in per unit on a 100 MVA base, and the line charging
susceptances are neglected. Obtain the power flow solution by the Gauss-Seidel
method including line flows and line losses.
1
2
0.02 + j0.04
400
MW
0.01 + j0.03
0.0125 + j0.025
250
Mvar
Slack Bus
3
V = 1.0520°
200
MW
| V3 = 1.04
Figure 6.12
Transcribed Image Text:Figure 6.12 shows the one-line diagram of a simple three-bus power system with generators at buses 1 and 3. The magnitude of voltage at bus 1 is adjusted to 1.05 pu. Voltage magnitude at bus 3 is fixed at 1.04 pu with a real power generation of 200 MW. A load consisting of 400 MW and 250 Mvar is taken from bus 2. Line impedances are marked in per unit on a 100 MVA base, and the line charging susceptances are neglected. Obtain the power flow solution by the Gauss-Seidel method including line flows and line losses. 1 2 0.02 + j0.04 400 MW 0.01 + j0.03 0.0125 + j0.025 250 Mvar Slack Bus 3 V = 1.0520° 200 MW | V3 = 1.04 Figure 6.12
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