Question

Asked Jun 4, 2019

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You are given that the system shown in Figure 4.25 has a 110/220 kV autotransformer. The positive- and zero-sequence impedances in ohms or percent are as shown in the figure, the zero-sequence impedances being in parentheses. Assume that the low- voltage system is solidly grounded. For a phase-a-to-ground fault at the midpoint of the transmission line, calculate the transformer current In in the neutral and the phase a currents Ia and I'a on the high and low sides of the transformer. If the source on the low-voltage side is to be grounded through a reactance, determine the value of the grounding reactance for which the transformer neutral current becomes zero. As the grounding reactance changes around this value, the direction of the neutral current will reverse, and will affect the polarizing capability of the neutral current for ground faults on the high side. Can faults on the low-voltage side ever cause the neutral current to reverse?

Step 1

Since there is single line to ground fault in phase a. So, fault current in phase a will be I_{F }and fault current in other phases will be zero.

For a single line to ground fault, zero sequence fault current* (I _{af}^{(0)}*), positive sequence fault current (

Step 2

Since positive sequence fault current is equal to the zero sequence fault current.

Calculate the zero sequence fault current *(I _{af}^{(0)}*) to get the current in neutral ground also current in high voltage and low voltage side of autotransformer.

So calculate the zero sequence fault current. For calculating the zero sequence fault current, draw the Thevenin’s equivalent circuit for positive sequence, negative sequence and zero sequence. Then calculate the equivalent Thevenin’s voltage and resistance for each sequence.

For solving the question further

Assume

Step 3

Since transmission line is connected on high voltage site and impedance of transmission line is the actual value. So convert t...

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