Figure a shows a rod of resistive material. The resistance per unit length of the rod increases in positive direction of the X axis. At any position along the rod, the resistance dR of a narrow- differential-section of width dx is given by dR 5.00xdx, where dR is in ohms and a in meters. Figure b shows such a narrow section. You are to slice off a length of the rod between X = O and some position = L and then connect that length to a battery with potential difference V = 5.0V (Fig. c). You want the current in the length to transfer energy to therma energy at the rate of 6.2 W. At what position x = L in meters should you cut the rod? Keep decimla points in your aanswer. = dx 1.0 -x (m)

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter28: Current And Resistance
Section: Chapter Questions
Problem 68PQ
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Figure a shows a rod of resistive material. The
resistance per unit length of the rod increases in the
positive direction of the X axis. At any position x
along the rod, the resistance dR of a narrow-
differential-section of width dx is given by
dR = 5.00xdx, where dR is in ohms and is
in meters. Figure b shows such a narrow section.
You are to slice off a length of the rod between
X = O and some position = L and then
connect that length to a battery with potential
difference V = 5.0V (Fig. c). You want the
current in the length to transfer energy to thermal
energy at the rate of 6.2 W. At what position
x = L in meters should you cut the rod? Keep 2
decimla points in your aanswer.
dx
1.0
-x (m)
Transcribed Image Text:Figure a shows a rod of resistive material. The resistance per unit length of the rod increases in the positive direction of the X axis. At any position x along the rod, the resistance dR of a narrow- differential-section of width dx is given by dR = 5.00xdx, where dR is in ohms and is in meters. Figure b shows such a narrow section. You are to slice off a length of the rod between X = O and some position = L and then connect that length to a battery with potential difference V = 5.0V (Fig. c). You want the current in the length to transfer energy to thermal energy at the rate of 6.2 W. At what position x = L in meters should you cut the rod? Keep 2 decimla points in your aanswer. dx 1.0 -x (m)
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