Fill-in Questions: 1. The forward voltage across a silicon diode in a normally working circuit is V. 2. A resistor in series with the diode of question 1 would have voltage drop equal to the minus the voltage drop of the 3. If the diode in question 1 were to open, the voltage drop across it would be V. (Hint: refer to figure 1-2b)

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
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Chapter12: Electronic Control Devices
Section: Chapter Questions
Problem 3RQ: Diodes and rectifiers allow current to _________. flow in one direction only flow in both...
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Apparatus/Materials:
 1 Variable Low-Voltage power supply 
 1 Standard or Digital Voltmeter
 1 1KΩ Resistor at 0.5W
 1 n4001 Silicon Diode or Similar Type
 1 Breadboard for constructing circuit 

Fill-in Questions:
1. The forward voltage across a silicon diode in a normally working circuit
is
V.
2. A resistor in series with the diode of question 1 would have voltage drop equal to the
minus the voltage drop of the
3. If the diode in question 1 were to open, the voltage drop across it would be
V. (Hint: refer to figure 1-2b)
Transcribed Image Text:Fill-in Questions: 1. The forward voltage across a silicon diode in a normally working circuit is V. 2. A resistor in series with the diode of question 1 would have voltage drop equal to the minus the voltage drop of the 3. If the diode in question 1 were to open, the voltage drop across it would be V. (Hint: refer to figure 1-2b)
Introduction:
Referring to Figure 1-2.a note that the forward-biased silicon diode has a voltage drop of 0.7V
across it with the remaining power supply voltage dropped across the load resistance (RL).
The voltage drop of R₁ can be found by the formula VL = Vdd - Vf. The forward current (IF)
through the circuit can be found by the formula ID = VL/RL. Referring to Figure 1-2b, note that
a reverse-biased silicon diode has the total power supply voltage dropped across it, while the
voltage drop across the load resistor is zero, since no current is flowing in the circuit.
Vdd = +6 V
Vdd = +6 V
D1
RL
VF
VL
Figure 1-2.a
D1
RL
Im
VF
VL
Figure 1-2.b
Transcribed Image Text:Introduction: Referring to Figure 1-2.a note that the forward-biased silicon diode has a voltage drop of 0.7V across it with the remaining power supply voltage dropped across the load resistance (RL). The voltage drop of R₁ can be found by the formula VL = Vdd - Vf. The forward current (IF) through the circuit can be found by the formula ID = VL/RL. Referring to Figure 1-2b, note that a reverse-biased silicon diode has the total power supply voltage dropped across it, while the voltage drop across the load resistor is zero, since no current is flowing in the circuit. Vdd = +6 V Vdd = +6 V D1 RL VF VL Figure 1-2.a D1 RL Im VF VL Figure 1-2.b
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